The equilibrium equation of force in horizontal direction is, TA Cos 30° = TB cos 45° TA = 0.81657 • Ta is the tension in cord A • TB is the tension in cord B (1) The equilibrium equation of force in vertical direction is, TA sin 30° + Tu sin 45° = Tc (II) Te is the tension in cord C The equilibrium equation of force for suspended object is, Tc = w (III) • Te is the tension in cord C • wis weight of suspended object Conclusion: Substitute 0.8165T, for TA and w for Te in eqs. (II) to find TB Tg. (0.8165TR) sin 30° + Tg sin 45° = w 1.1157g = w TB = 0.897w Substitute 0.897w for Tg in equation (I) to find TA TA. TA = 0.8165 x (0.897w) TA = 0.732w Therefore tension in cord A is 0.732w. Tension in cord B is 0.897w. Tension in cord C is w.

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The equilibrium equation of force in horizontal direction is,
TA Cos 30° = TB cos 45°
TA = 0.81657
• Ta is the tension in cord A
• TB is the tension in cord B
(1)
The equilibrium equation of force in vertical direction is,
TA sin 30° + Tu sin 45° = Tc (II)
Te is the tension in cord C
The equilibrium equation of force for suspended object is,
Tc = w (III)
• Te is the tension in cord C
• wis weight of suspended object
Conclusion:
Substitute 0.8165T, for TA and w for Te in eqs. (II) to find TB Tg.
(0.8165TR) sin 30° + Tg sin 45° = w
1.1157g = w
TB = 0.897w
Substitute 0.897w for Tg in equation (I) to find TA TA.
TA = 0.8165 x (0.897w)
TA = 0.732w
Therefore tension in cord A is 0.732w. Tension in cord B is 0.897w. Tension
in cord C is w.
Transcribed Image Text:The equilibrium equation of force in horizontal direction is, TA Cos 30° = TB cos 45° TA = 0.81657 • Ta is the tension in cord A • TB is the tension in cord B (1) The equilibrium equation of force in vertical direction is, TA sin 30° + Tu sin 45° = Tc (II) Te is the tension in cord C The equilibrium equation of force for suspended object is, Tc = w (III) • Te is the tension in cord C • wis weight of suspended object Conclusion: Substitute 0.8165T, for TA and w for Te in eqs. (II) to find TB Tg. (0.8165TR) sin 30° + Tg sin 45° = w 1.1157g = w TB = 0.897w Substitute 0.897w for Tg in equation (I) to find TA TA. TA = 0.8165 x (0.897w) TA = 0.732w Therefore tension in cord A is 0.732w. Tension in cord B is 0.897w. Tension in cord C is w.
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