The ferritin gene encodes an IRE (Iron-response element) within the 5 UTR (untranslated region) of the MRNA Considering what you know about eukaryotic translation the IRE-BP (Iron Response Element Binding Protein) is bound to the IRE in the 5UTR you would expect: That the presence of the IRE-BP would enhance translation. That the presence of the IRE-BP would have no effect. That the presence of the IRE-BP would block translation O I don't remember enough about the IRE-BP or transiation to guess.

The ferritin gene encodes an IRE (Iron-response element) within the 5 UTR (untranslated region) of the MRNA Considering what you know about eukaryotic translation the IRE-BP (Iron Response Element Binding Protein) is bound to the IRE in the 5UTR you would expect: That the presence of the IRE-BP would enhance translation. That the presence of the IRE-BP would have no effect. That the presence of the IRE-BP would block translation O I don't remember enough about the IRE-BP or transiation to guess.

Name: Modifications of histone tails can:O repress the transcription of som
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Description: Modifications of histone tails can:O repress the transcription of some genesaffect chromatin structureaffect the transcription of some genes in response to the diet or environmentactivate the transcription of some genesall of these choices are corre

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter9: Gene Expression And Gene Regulation

Section: Chapter Questions

Problem 17QP: Given the following mRNA, write the double-stranded DNA segment that served as the template....

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Given the following mRNA, write the double-stranded DNA segment that served as the template. Indicate both the 5 and the 3 ends of both DNA strands. Also write out the tRNA anticodons and the amino acid sequence of the protein encoded by the mRNA message. DNA: mRNA: 5-CCGCAUGUUCAGUGGGCGUAAACACUGA-3 protein: tRNA:
Prokaryotic cells can have more than one functional start codon per mRNA because There are multiple answers A prokaryotic promotes consist of two separated sequences: the -30 box and the -10 box B they make polycistronic RNA C both transcription and translation happen in the same cellular compartment D prokaryotic ribosomes bind to the Shine-Delgarno sequence E the activity of the lac repressor is regulated based on the physiologic condition of the cell
I've attached the table of transcription ans translation for a DNA and Bees work, Genes A and B are exons while C is an intron. Gene A has a silent mutation and Gene B has a nonsense mutation. Please answer the below for me The 3 genes code for different proteins: • Gene A = protein essential for stinger • Gene B = DNA replication enzyme • Gene C = fuzzy hair protein Do you think it matters which protein is mutated? Is one protein more important than another? How would you try to help the bees stay healthy using the information from the mutations?
Compared to heterochromatin, euchromatin is comprised of densely packed nucleosomes and with higher transcription activity comprised of densely packed nucleosomes and with lower transcription activity O comprised of loosely packed nucleosomes and with lower transcription activity Ocomprised of loosely packed nucleosomes and with higher transcription activity
Arrange the processes involved from Transcription to Translation. RNA polymerase binds in the promoter regions Polypeptide cleavage Release of methionine and conversion to active protein Translocation Appearance of UAG codon Attachment of the mRNA to ribosome with AUG in the P site DNA rejoins Covalent bonding of AA to the tRNA Elongation of RNA transcript Binding of Rho factor Partial unwinding of DNA
RNA polymerase O Transcription to produce pre-mRNA O Post- transcriptional modification Nuclear pore complex OExport of mature mRNA into cytoplasm OPost- Ribosome with transfer RNAS translational O Translation of OProtein folding modifications. mature mRNA Look at the image above: 3. Where does transcription specifically take place in the cell? 4. Where does translation specifically take place in the cell?
Why would it be impossible for DNA splicing to occur utilizing the same mechanism as eukaryotic MRNA splicing? Spliced DNA could not be transcribed or translated DNA does not have a 3'-OH group for the initial nucleophilic attack that forms the lariat O DNA does not encode introns O DNA does not have a 2'-OH group for the initial nucleophilic attack that forms the lariat
EF-Ts factor regenerates EF-Tu/GDP from EF-Tu/GTP for the next round of elongation cycle in prokaryotic translation. The sigma subunit of RNA polymerase is replaced by NusA to recognise the promoter region of a gene. The -10 and -35 sequences in E. coli DNA are referred to as untranslated region. In human, translation begins before transcription of an mRNA completes. this statement true or false.
Select the processes that only happen inside the nucleus of a eukaryotic cell. Select all that apply. O making tRNA O transcribing rRNA O removing introns from precursor mRNA O transcriptional initiation at the promoter O adding the polyA tail O mRNA binding to the small ribosomal subunit ORNA splicing O tRNA binding to codons
Transcription of a typical gene encoding a polypeptide in eukaryotes involves all of the following EXCEPT: transcription of DNA corresponding to both introns and exons. transcription of the DNA corresponding to the gene of the polypeptide which may include UTRS (c) RNA synthesis by RNA polymerase II. the splicing together of a number of exons in the DNA prior to transcription.
Identify the DNA elements and protein factors, #1-7, in the figure below that are involved in the initiation and elongation of transcription at a eukaryotic promoter of a gene TRANSCRIPTION ON RNA PROCESSING PefA A eukaryotic promoter commonly includes a TATA box (a nucleotide sequence TRANSLATION Ritoom containing TATA) about 25 nucleotides upstream from Nontemplate (coding) strand of DNA 7 Pupeptide 1 the transcriptional start point. Nontemplate (coding or sense) strand DNA TATAAAA ATATILTI 5 2 3 Start point 2 Several transcription TCCAA 3' 5' factors, one recognizing the TATA box, must bind 3' end to the DNA before RNA 4 polymerase Il can bind in the correct position and orientation. UCCA 3 5' 3' 3 Additional transcription GGTT factors (purple) bind to the DNA along with RNA 5' Direction of transcription polymerase II, forming the transcription initiation 3 complex. RNA polymerase Il then unwinds the DNA double helix, and RNA synthesis begins at the start point on the temple strand.…
Cordycepin (structure shown), a broad-spectrum antibiotic was used to treat a bacterial infection. What genetic mechanism would it most likely inhibit? NH2 но. ÓH Replication Post-transcriptional modification Translation Reverse transcription All of these