The following thermochemical equation is for the reaction of HCl(g) with NH3 (9) to form NH4Cl(s) HCl(g) + NH3(g) → NH₂Cl(s) AH = - 176 kJ How many grams of HCl(g) would have to react to produce 59.0 kJ of energy? grams
The following thermochemical equation is for the reaction of HCl(g) with NH3 (9) to form NH4Cl(s) HCl(g) + NH3(g) → NH₂Cl(s) AH = - 176 kJ How many grams of HCl(g) would have to react to produce 59.0 kJ of energy? grams
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Chapter6: Thermochemisty
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![The following thermochemical equation is for the reaction of HCl(g) with NH3(g) to form NH4Cl(s).
HCl(g) + NH3(g) → NH4Cl(s) AH = -176 kJ
How many grams of HCl(g) would have to react to produce 59.0 kJ of energy?
grams](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe6ce2240-b3fe-4331-98ee-3937416f40f5%2F06a951ef-33d5-4dfd-8222-cb602e8c14f5%2F0vswwne_processed.png&w=3840&q=75)
Transcribed Image Text:The following thermochemical equation is for the reaction of HCl(g) with NH3(g) to form NH4Cl(s).
HCl(g) + NH3(g) → NH4Cl(s) AH = -176 kJ
How many grams of HCl(g) would have to react to produce 59.0 kJ of energy?
grams
Expert Solution
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Step 1
This is exothermic reaction as of the reaction is negative.
1 mole ammonia react with 1 mole hydrogen chloride and 176 KJ heat produced.
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