The free energy change for the following reaction at 25 °C, when [Cd2+] = 9.08x10-3 M and [Ni2+] = 1.18 M, is 41.6 kJ: Cd2+(9.08x10-3 M) + Ni(s)→ cd(s) + Ni2+(1.18 M) AG = 41.6 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction v forward reverse
The free energy change for the following reaction at 25 °C, when [Cd2+] = 9.08x10-3 M and [Ni2+] = 1.18 M, is 41.6 kJ: Cd2+(9.08x10-3 M) + Ni(s)→ cd(s) + Ni2+(1.18 M) AG = 41.6 kJ What is the cell potential for the reaction as written under these conditions? Answer: V Would this reaction be spontaneous in the forward or the reverse direction v forward reverse
Chemistry by OpenStax (2015-05-04)
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Chapter17: Electrochemistry
Section: Chapter Questions
Problem 24E: For each reaction listed, determine its standard cell potential at 25 C and whether the reaction is...
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![The free energy change for the following reaction at 25 °C, when [Cd2+]
= 9.08x10-3 M and [Ni2+] = 1.18 M, is 41.6 kJ:
Cd2+(9.08x10-3 M) + Ni(s)–
Cd(s) + Ni2+(1.18 M)
AG = 41.6 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction
forward
reverse](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc329d18c-c774-4ef9-9f68-4a57fcf783f7%2F977cb550-153e-4381-9d6d-a428cd0583e3%2Fy1bgk5j_processed.png&w=3840&q=75)
Transcribed Image Text:The free energy change for the following reaction at 25 °C, when [Cd2+]
= 9.08x10-3 M and [Ni2+] = 1.18 M, is 41.6 kJ:
Cd2+(9.08x10-3 M) + Ni(s)–
Cd(s) + Ni2+(1.18 M)
AG = 41.6 kJ
What is the cell potential for the reaction as written under these conditions?
Answer:
V
Would this reaction be spontaneous in the forward or the reverse direction
forward
reverse
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