- The general solution of the equation dy dx = (1 + y²) cos x is y(x) = tan(C + sin x). With the initial condition y (0) = 0 the solution y(x) = tan(sin x) is well behaved. But with y(0) = 1 the solution y(x) = tan (7 + sin x) has a ver- tical asymptote at x = sin(1/4) z 0.90334. Use Euler's method to verify this fact empirically. ) =ta

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.5: Derivatives Of Logarithmic Functions
Problem 47E
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- The general solution of the equation
dy
dx
= (1 + y²) cos x
is y(x) = tan(C + sin x). With the initial condition y (0) =
0 the solution y(x) = tan(sin x) is well behaved. But with
y(0) = 1 the solution y(x) = tan (7 + sin x) has a ver-
tical asymptote at x = sin(1/4) z 0.90334. Use Euler's
method to verify this fact empirically.
) =ta
Transcribed Image Text:- The general solution of the equation dy dx = (1 + y²) cos x is y(x) = tan(C + sin x). With the initial condition y (0) = 0 the solution y(x) = tan(sin x) is well behaved. But with y(0) = 1 the solution y(x) = tan (7 + sin x) has a ver- tical asymptote at x = sin(1/4) z 0.90334. Use Euler's method to verify this fact empirically. ) =ta
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