New Jave code must be entered inbetween grey blocks of code as seen in photo The inverse of current is 1/ current. The following program computes the inverse of a measurement of current and then outputsthe inversed value. The code contains errors. Find and fix the errors.Ex: If the input is 0.500, then the output is:The inverse of current = 1 / 0.500 = 2.0001 import java.util.Scanner;3 public class CurrentInverse {N&00245678910111213141516Pee6717public static void main(String[] args) {Scanner scnr = new Scanner(System.in);/* Modify the following code */int current;int currentInverse;current scnr.nextInt ();currentInverse = 1 / current;System.out.printf("The inverse of current = 1 / %.3f", current);System.out.printf(" = %.3f\n", currentInverse);

Import the required Java utility class Scanner.Define a Java class called "CurrentInverse."In the…

The inverse of current is 1/ current. The following program computes the inverse of a measurement of current and then outputs the inversed value. The code contains errors. Find and fix the errors. Ex: If the input is 0.500, then the output is: The inverse of current = 1 / 0.500 = 2.000 1 import java.util.Scanner; 2 3 public class CurrentInverse { 4 5 6 7 8 9 10 11 12 13 14 15 16 17 public static void main(String[] args) { Scanner scnr = new Scanner(System.in); /* Modify the following code */ int current; int currentInverse; current scnr.nextInt (); currentInverse = 1 / current; System.out.printf("The inverse of current = 1 / %.3f", current); System.out.printf(" = %.3f\n", currentInverse);

The inverse of current is 1/ current. The following program computes the inverse of a measurement of current and then outputs the inversed value. The code contains errors. Find and fix the errors. Ex: If the input is 0.500, then the output is: The inverse of current = 1 / 0.500 = 2.000 1 import java.util.Scanner; 2 3 public class CurrentInverse { 4 5 6 7 8 9 10 11 12 13 14 15 16 17 public static void main(String[] args) { Scanner scnr = new Scanner(System.in); /* Modify the following code */ int current; int currentInverse; current scnr.nextInt (); currentInverse = 1 / current; System.out.printf("The inverse of current = 1 / %.3f", current); System.out.printf(" = %.3f\n", currentInverse);

C++ for Engineers and Scientists

4th Edition

ISBN:9781133187844

Author:Bronson, Gary J.

Publisher:Bronson, Gary J.

Chapter5: Repetition Statements

Section5.5: A Closer Look: Loop Programming Techniques

Problem 14E

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