The moment of inertia of a fluorine (F2) molecule is 3.167 × 10-46. What is the rotational energy of a fluorine molecule in electron volts for the 19 state? (h = 6.626 × 10-34 J s, 1.055 x 10-34 J s, 1 eV = 1.60 × 10-19 J){E} - - You Answered 0.0417 Correct Answers 0.0042 4.2 × 10-2

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter15: Molecular Luminescence Spectrometry
Section: Chapter Questions
Problem 15.2QAP
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The moment of inertia of a fluorine (F2) molecule is 3.167 × 10-46. What is the rotational energy of a fluorine molecule in electron volts
for the 19 state? (h = 6.626 × 10-34 J s, 1.055 x 10-34 J s, 1 eV = 1.60 × 10-19 J){E}
-
-
You Answered
0.0417
Correct Answers
0.0042
4.2 × 10-2
Transcribed Image Text:The moment of inertia of a fluorine (F2) molecule is 3.167 × 10-46. What is the rotational energy of a fluorine molecule in electron volts for the 19 state? (h = 6.626 × 10-34 J s, 1.055 x 10-34 J s, 1 eV = 1.60 × 10-19 J){E} - - You Answered 0.0417 Correct Answers 0.0042 4.2 × 10-2
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