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- Use your knowledge of condensation reactions to complete the following tasks. Protein: Draw a condensation reaction where a molecule of cysteine combines with a molecule of lysine, showing all reactants and products, and labeling a peptide linkage in your final product. Make sure the structures you draw include all hydrogens (leave every bond labeled and included in your drawing; don't use shorthand). Carbohydrate: Draw two ringed a-D glucose monomers forming a disaccharide (maltose). Make sure to label the glycosidic linkage formed.The following compound is a(n) CH200(CH2)14CH3 CHOC CH2)14CH3 monosaccharide triglyceride O harmone steriod dipeptide CH,OH CHOH CHOH is a OH H OH H OH H %3D H OH OH O polyamide O polypeptide O polyester O polysaccharide O polyurethane. Draw the product in the following reactions; LIAIHĄ A но OH B H2SO4 OH 1. LAH 2. 2-propanone, H* C CH;OH, H* D 1. NACN 2. H2SO4, H20 NABH4 OH E F Ans . Show the ring closure scheme for the glucose molecule. Ans
- 12:08 PM Thu Apr 28 @ 61% HW 13 Home Insert Draw Layout Review View Calibri Light Regu 12 ΒΙυ U A unsaturated b. -C(CH,),CH=CH(CH,),CH3 8ölid С. || -C(CH,)16CH; Saterated 54. Classify each of the following carbohydrates as a monosaccharide, dissaccharide, or polysaccharide: CH,OH H 0- н СН,ОН 0 H а. H ОН Н H OH НО CH,OH OH ОН H H H-C-0H НО—С—Н H-C-OH Н—С—ОН CH,OH HOCH2 CH,OH С. H. Но OCH2CH3 OH H CH,OH CH,OH CH,OH H -0 H H -0 H H H d. H. ОН Н ОН Н ОН Н ОН H OH H ОН 58. Classify each molecule as a lipid, carbohydrate, or amino acid: CH,0C(CH,)12CH, а. l'pid CHOC(CH,),4CH3 CH;0C(CH,),CH=CH(CH,);CH; b.Two sugars differing in configuration at a single asymmetric carbon atom are known as epimers. D-mannose is a C-2 epimer of glucose (Structure I), while D-galactose is a C-4 epimer of glucose. Structure Il and IIl are H- -OH но- -H H OH HO H но- H HO H H -OH H- -OH HO OH H -OH H- -OH H OH HO. HO, OH II II Which of the following represents an aldopentose? OH H O HO O HO H но н HO H но- HO H HO H HO- H OH H OH H OH H OH OH HO Он of но" HO O OH он III IV These are chemical messengers that are secreted by endocrine glands and carried through the bloodstream to target tissues. prostaglandin deoxysugar glycoside hormones Which of the following is NOT correctly paired? cellulose: beta-1,4-glycosidic linkage amylose: alpha-1,4-glycosidic linkage chitosan: alpha-1,4-glycosidic linkage cellubiose: beta-1,4-glycosidic linkageF s fill A phosphodiester bond is the bond formed between the PDF NOFFIC RANSCR 0 stly cloudy 0-P-0-CH₂ 0 + H 0 5' 0 0=P-0-CH₂ Base Sugar 3' OH Base Sugar OH Free 5' phosphate 0 0 P 0 5' O-CH₂ Sugar 3' O N Base Phosphodiester 0=P-0-CH₂ linkage Sugar 3' OH Free 3' hydroxyl O 2' hydroxyl group of the sugar in one nucleotide and the phosphate group on the 5' carbon atom in the sugar of the next nucleotide O 3' hydroxyl group of the sugar in one nucleotide and the phosphate group on the 5' carbon atom in the sugar of the next nucleotide O 3' phosphate group of the sugar in one nucleotide and the phosphate group on the 5' carbon atom in the sugar of the next nucleotide O 3' hydroxyl group of the sugar in one nucleotide and the phosphate group on the 1' carbon atom in the sugar of the next nucleotide + H₂O N Base O Search PD ac pe huniz recor PD maste omiss
- Which of the following is NOT correctly paired? - cellulose: beta-1,4-glycosidic linkage - amylose: alpha-1,4-glycosidic linkage - chitosan: alpha-1,4-glycosidic linkage - cellubiose: beta-1,4-glycosidic linkage H- -OH HO H H OH но- Но но- -- H- -OH H- -OH но- -OH H- -OH- -OH H OH OH он OH II Two sugars differing in configuration at a single asymmetric carbon atom are known as epimers. D-mannose is a C-2 epimer of glucose (Structure I), while D-galactose is a C-4 epimer of glucose. Structure || and III are II: galactose, Ill: mannose Il: mannose; II: galactose Il and III are mannose Il and III are galactose OH ÇOOH HO H H OH H OH COOH HO H но, но, II What will be the result if Structure III is subjected to Benedict's test? solution will change to red solution will change to purple silver mirror will form no change in colorWhich of the following represents an aldopentose? H. но. LO но но -H HO H -- HO H- -- Но -H HO H- но H- -O- -OH H- -OH H- -OH -O- OH OH HO HO. OH II II IV V Which of the following is NOT correctly paired? cellulose: beta-1,4-glycosidic linkage amylose: alpha-1,4-glycosidic linkage chitosan: alpha-1,4-glycosidic linkage cellubiose: beta-1,4-glycosidic linkage are involved in the regulation of glucose metabolism and in the control of inflammation, while control tissue swelling by regulating cellular salt balance between Na+ and K+. glucocorticoids, mineralocorticoids mineralocorticoids, glucocorticoids androgen, estrogen estrogen, androgen The type of glycosidic bond present in the structure is CH2OH H H. H CH2OH он OH H. -0 ÓH CH2OH он он OH H H CH2OH H ÓH он H. H H. Он OH но H OHConsider the following carbohydrate and choose the best description below. НО CH 2OH ОН ОҢ O There are no reducing ends O The bonds shown are alpha-1,4-O-glycosidic bonds O Each monosaccharide is a ketone in the branched structure O Each O-glycosidic bond shown is in the beta configuration O This is a disaccharide CH 2OH 2 ОН ОН CH 2OH ОН 3 ОН ОН
- An aldohexose (e.g., Glucose) can occur in three forms: two cyclic forms and one open-chain structure in aqueous solution. 5. H-C-OH H (a) н-сто (b) (c) CH₂OH OH ОН aldotriose H H-C=O H-C-OH H-C-OH H-C-OH CH₂OH OH OH OH OH aldopentose Draw the corresponding structures of aldohexoses (c.f., aldotriose and aldopentose). aldohexose Draw the reaction forming two cyclic forms from the open-chain structure How many asymmetric carbon atoms (chiral centers) are there in three forms, respectively?Naming and drawing cyclic monosaccharides Give the complete common name, including anomer and stéreochemistry labels, of the following molecule resource. OH H HOCH₂ H HOCH₂ H H CH₂OH H Н HOCH₂ OH OH H H OH OH OH H 0 H OH Н OH Н OH H OH OH OH CH₂OH H OH D a BY 518-52 Classify cach of the following monosaccharides as an aldose or a ketose. CHO HO-C-H ÇH,OH re-ee HO'H C=0 HO-C-H HO-C-H HO-C-H HO-C-H H-C-OH CH;OH CH;OH с. CHO d. CH;OH HO-C-H C=0 H-C-OH HO-C-H CH,OH HO-Ć-H H-C-OH 18 CH;OH 18-53 Classif
