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The Newtower Company has experienced a 3.2% rate of customer complaints and attempts to lower this rate with an employment training program. After the program, the complaint rate is dropped to 1.5%. For a sample of 250 customers, find the mean and standard deviation for the number of complaints in this group of 250 customers. o² = 250 x 0.015 = 3.75,0 = 1.936 μ = 250+ 1.5 = 166.67 μ=150 o² = 250 x 0.015 x 0.985 = 3.694, o = 1.922 0²= 250 x 0.15 x 0.85 = 31.875,= 5.656

The Newtower Company has experienced a 3.2% rate of customer complaints and attempts to lower this rate with an employment training program. After the program, the complaint rate is dropped to 1.5%. For a sample of 250 customers, find the mean and standard deviation for the number of complaints in this group of 250 customers. o² = 250 x 0.015 = 3.75,0 = 1.936 μ = 250+ 1.5 = 166.67 μ=150 o² = 250 x 0.015 x 0.985 = 3.694, o = 1.922 0²= 250 x 0.15 x 0.85 = 31.875,= 5.656

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
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The Newtower Company has experienced a 3.2% rate of customer complaints and attempts to lower this rate with an employment training program. After the program, the complaint rate is dropped to 1.5%. For a sample of 250 customers, find the mean and standard deviation for the number of complaints in this group of 250 customers. o² = 250 x 0.015 = 3.75,0 = 1.936 μ = 250 ÷ 1.5 = 166.67 μ = 150 o² = 250 x 0.015 x 0.985 = 3.694, o = 1.922 o² = 250 x 0.15 x 0.85 = 31.875, o = 5.656
Transcribed Image Text:The Newtower Company has experienced a 3.2% rate of customer complaints and attempts to lower this rate with an employment training program. After the program, the complaint rate is dropped to 1.5%. For a sample of 250 customers, find the mean and standard deviation for the number of complaints in this group of 250 customers. o² = 250 x 0.015 = 3.75,0 = 1.936 μ = 250 ÷ 1.5 = 166.67 μ = 150 o² = 250 x 0.015 x 0.985 = 3.694, o = 1.922 o² = 250 x 0.15 x 0.85 = 31.875, o = 5.656
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