The position of a particle along a coordinate axis at time t (in seconds) is given by s(t)=-3t2-4t+1 (in meters). Find the function that describes its acceleration at time t.
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- A pirate has buried his treasure on an island with five trees located at the points (30.0 m, 20.0 m), (60.0 m, 80.0 m), (10.0 m, 10.0 m), (40.0 m, 30.0 m), and (70.0 m, 60.0 m), all measured relative to some origin, as shown in Figure P1.69. His ships log instructs you to start at tree A and move toward tree B, but to cover only one-half the distance between A and B. Then move toward tree C, covering one-third the distance between your current location and C. Next move toward tree D, covering one-fourth the distance between where you are and D. Finally move toward tree E, covering one-fifth the distance between you and E, stop, and dig. (a) Assume you have correctly determined the order in which the pirate labeled the trees as A, B, C, D, and E as shown in the figure. What are the coordinates of the point where his treasure is buried? (b) What If? What if you do not really know the way the pirate labeled the trees? What would happen to the answer if you rearranged the order of the trees, for instance, to B (30 m, 20 m), A (60 m, 80 m), E (10 m, 10 m), C (40 m, 30 m), and D (70 m, 60 m)? State reasoning to show that the answer does not depend on the order in which the trees are labeled. Figure 1.69A point moves in a circle at a constant speed of 35cm/sec. The period of one complete journey around the circle is 20sec. At t = 0 the line to the point from the center of the circle makes an angle of 30° with the x axis. a) Obtain the equation of the x coordinate of the point as a unction of time, in the form x = A cos (ωt + φ), giving the numerical values of A, ꞷ and φ. b) What are the values of x, dx/dt, and d2x/dt2 at t = 4 sec.The position of a particle in space at time tis: r(t) = (sec(t)) * i + (tan t) * j + 4/3 tk. Write the particle's velocity at time t = (pi / 6) as the product of its speed and direction.
- A particle moves ccw on a circular path of 400 ft radius. It starts from a fixed point which is horizontally to the right of the center of the path and moves so that s = 10t2 + 20t where s is the arc distance in ft and t is the time in sec. Compute the x and y components of the acceleration at the end of 3 seconds.The equation r(t) = (/2t) i+ (/2t- 16t2) j is the position of a particle in space at time t. Find the angle between the velocity and acceleration vectors at time t= 0. The angle between the velocity and acceleration vectors at time t = 0 is radians. (Type an exact answer, using n as needed.)Given that the acceleration vector is a(t)=(−16cos(−4t))i+(−16sin(−4t))j+(1t)k, the initial velocity is v(0)=i+k, and the initial position vector is r(0)=i+j+k, compute: A. The velocity vector v(t) B. The position vector r(t)
- A particle is moving with the given data. Find the position of the particle. a(t) = 5 sin t – 2 cos t, s(0) = 0, s(2n) = 4 Position s(t)√√3 =(√³1) 1+ (1-161²) The equation r(t) = vectors at time t = 0. j is the position of a particle in space at time t. Find the angle between the velocity and acceleration The angle between the velocity and acceleration vectors at time t= 0 is (Type an exact answer, using as needed.) radians.The equation r(t) = ( sin t)i + ( cos t)j + (t) k is the position of a particle in space at time t. Find the particle's velocity and acceleration vectors. π Then write the particle's velocity at t= as a product of its speed and direction. The velocity vector is v(t) = (i+j+ k.
- The position of an object as a function of time is given by r = (3.2t + 1.5t2)i + (1.7t -2.0t2)jm, where t is time in seconds. What is the magnitude of the acceleration, and what is the direction of the acceleration (given in terms of theta, clockwise from the x axis).An object's velocity as a function of time in one dimension is given by the expression; v(t) = 3.8t + 6.68 where are constants have proper SI Units. At what time is the object's velocity 61.2 m/s?At time t = 0 a particle at the origin of an xyz-coordinate system has a velocity vector of vo = i+ 5j – k. The acceleration function of the particle is a(t) = 32r²i + j+ (cos 21)k. Find the speed of the particle at time t = 1. Round your answer to two decimal places.