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- Draw the ERD rI : ithat is implemented by the following SQL code: CREATE TABLE PROJ_USER USER_ID NUMBER NOT NULL, USER_NAME VARCHAR2(50) NOT NULL, USER_EMAIL VARCHAR2(50) NOT NULL, CONSTRAINT USER_PK PRIMARY KEY (USER_ID) ); CREATE TABLE PROJ_CERTIFIEDUSER USER_ID NUMBER NOT NULL, CUSER_REALNAME VARCHAR2(50) NOT NULL, CUSER_CERTIFICATION VARCHAR2(50) NOT NULL, CONSTRAINT CERTIFIEDUSER_PK PRIMARY KEY (USER_ID), CONSTRAINT CERTIFIEDUSER_FK FOREIGN KEY (USER_ID) REFERENCES PROJ_USER (USER_ID) );The database contains a Horse table, with columns: ID integer, primary key Registered Name variable-length string. The database contains a Student table, with columns: • ID integer, primary key First Name - variable-length string LastName variable-length string Write a SQL Query to create a Schedule table, with columns: HorseID - integer with range 0 to 65535, not NULL • Student ID integer with range 0 to 65535 Lesson DateTime - date/time, not NULL (HorseID, Lesson DateTime) is the primary key Also, create the following foreign key constraints on Schedule columns: HorseID references Horse. When an ID is deleted from Horse matching Lesson Schedule rows are deleted. Student ID references Student. When an ID is deleted from Student, matching Student ID 's are set to NULL).Modify the ApplicationListing query to meet following requirements: The query should select all records with Administrative Assistant or User Support Director in the JobTitle Field. The records should be sorted in ascending order first by LastName and then by FirstName I have attached the image for help.
- Create a query that that returns staff members’ names (excludingdoctors), their hourly rates, number of hours worked and Salary(calculated column; there are 13 employees in the clinic) for the twoweeks period Create a query that returns all patients enrolled permanently with one ofthe doctors Create a query that would create a list of all patients that were seen by aparticular doctor on a given date (i.e. 12 December, 2020)select * from cast where cast_id=162652763; Use explain to display the query plan without creating any index. Now create an index to speed up the query. Use explain and timer to show the improvement.Draw the ERD. _that is implemented by the following SQL code: CREATE TABLE PROJ_USER USER_ID NUMBER NOT NULL, USER_NAME VARCHAR2(50) NOT NULL, USER_EMAIL VARCHAR2(50) NOT NULL, CONSTRAINT USER_PK PRIMARY KEY (USER_ID) ); CREATE TABLE PROJ_CERTIFIEDUSER USER_ID NUMBER NOT NULL, CUSER_REALNAME VARCHAR2(50) NOT NULL, CUSER_CERTIFICATION VARCHAR2(50) NOT NULL, CONSTRAINT CERTIFIEDUSER_PK PRIMARY KEY (USER_ID), CONSTRAINT CERTIFIEDUSER_FK FOREIGN KEY (USER_ID) REFERENCES PROJ_USER (USER_ID) );
- Hi, I have the query below and I get it to run, but it is missing something how to answer the problem. My joins appear to be incorrect, I am using ID_number and S_ID. so I am completely lost there. CREATE OR REPLACE PROCEDURE Moreno_03_insCourseNumsProc(INOUT i_ID VARCHAR(5))LANGUAGE PLPGSQLAS$$DECLAREname VARCHAR(35);tot_courses INTEGER; -- Created this variable to hold the total course taught by the instructor l_exists_count INTEGER := 0; -- This is to identify the existence of the records the table instructor_course_numsBEGINSELECT name INTO name FROM instructor WHERE instructor.id = i_id;SELECT COUNT(*) INTO tot_courses FROM teaches WHERE teaches.id = i_id;SELECT COUNT(*) INTO l_exists_count FROM instructor_course_nums WHERE ID_Number = i_ID; IF l_exists_count > 0THENUPDATE instructor_course_nums SET tot_courses = total_course_nums WHERE ID_Number = i_ID;ELSEINSERT INTO instructor_course_nums VALUES(i_ID, name, tot_courses);END IF;COMMIT; END;Which of the following statements is/are False? O Label encoding increases the overall number of dimensions O R square increases with number of independent variables O One hot encoding increases the overall number of dimensions O All of the above Which of the following is true about clustering? O Scaling the data is not necessary for clustering O K-means clustering results vary based on initialization points O Outlier treatment is not required for clustering O Categorical variables can be used in clustering without any preprocessingBelow are some rows of the table INVOICE COD PROV_COD DATE TYPE LOC TOTAL 2910 192 2022-03-11 90 TX 1928 9301 384 2022-05-03 90 NY 2800 Overdue invoices are those whose date plus TYPE days have passed. Which of the following shows all invoices with overdue dates? a. SELECT * FROM INVOICE WHERE CURDATE() - DATE > TYPE b. SELECT * FROM INVOICE WHERE CURDATE()-TYPE >DATE c. SELECT * FROM INVOICE WHERE DATE+TYPE < CURDATE() d. SELECT * FROM INVOICE WHERE DATE+TYPE > CURDATE()
- Given a database of bike share information write a SELECT statement to retrieve the bike_number, start_date, and end_date from trip_data and the station_id and name from bikeshare_stations where the start_station in trip_data is the same as the station_id in bikeshare_stations and where the member_type equals “Casual”. Limit the results to 5 rows. Please answer this python questionCreate a query based on tblEmployee and tblPurchase using the Find Unmatched Query Wizard that lists the EmployeelDFirstName, and LastName of any employee who has not yet made a sale. Save the query as qryEmployeeNoSales and then close the queryQuery 3: Write a parameter query to display the names of all prospects each member tried to recruit based on the member’s first name and the member’s last name you input. List the member’s First Name, member’s Last Name, prospect’s First Name, and prospect’s Last Name (in this order in the query grid). Display the member’s First Name Heading as Member First Name, member’s Last Name Heading as Member Last Name, prospect’s first name heading as Prospect First Name, and prospect’s last name heading as Prospect Last Name. Sort the list by Member Last Name, Member First Name, Prospect Last Name, and Prospect First Name, all ascending order. (WE ARE USING ACCESS SO I AM JUST TRYING TO UNDERSTAND WHAT TO PUT AND PLUG IN ETC. USE MY PICTURES AS REFERRENCE!)