The reaction H3C-1 OHH3C-OH+r may go by either of the following mechanisms: I) H3C-1 H3C++r (slow) H3C++ OH ® H3C-OH (fast) or II) H3C-1+ OHH3C-OH+I* If the first mechanism were correct, what would be the rate law? Rate = K[H3C-1] Rate = K[H3C-1][OH] Rate = k[H3C-1][OH-]2 Rate = K[H3C][OH] Rate = K[H3C+]

Chemistry: The Molecular Science
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Author:John W. Moore, Conrad L. Stanitski
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Chapter11: Chemical Kinetics: Rates Of Reactions
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The reaction
H3C-1 OHH3C-OH+r
may go by either of the following mechanisms:
I)
H3C-1
H3C++r
(slow)
H3C++ OH ® H3C-OH
(fast)
or
II)
H3C-1+ OHH3C-OH+I*
If the first mechanism were correct, what would be the rate law?
Rate = K[H3C-1]
Rate =
K[H3C-1][OH]
Rate = k[H3C-1][OH-]2
Rate =
K[H3C][OH]
Rate = K[H3C+]
Transcribed Image Text:The reaction H3C-1 OHH3C-OH+r may go by either of the following mechanisms: I) H3C-1 H3C++r (slow) H3C++ OH ® H3C-OH (fast) or II) H3C-1+ OHH3C-OH+I* If the first mechanism were correct, what would be the rate law? Rate = K[H3C-1] Rate = K[H3C-1][OH] Rate = k[H3C-1][OH-]2 Rate = K[H3C][OH] Rate = K[H3C+]
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