The reverberation time is 1.2 s for a room with dimensions of 6 m (L) x 4 m (W) x 3 m (H). What is the additional sound absorption area required to reduce the reverberation time to 1 s? Correct the final answer to 2 decimal places. Select one: a. 0.85 m2 b. 1.93 m2 c. 2.29 m2 d. 3.52 m2

The reverberation time is 1.2 s for a room with dimensions of 6 m (L) x 4 m (W) x 3 m (H). What is the additional sound absorption area required to reduce the reverberation time to 1 s? Correct the final answer to 2 decimal places. Select one: a. 0.85 m2 b. 1.93 m2 c. 2.29 m2 d. 3.52 m2

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter17: Physics Of Hearing

Section: Chapter Questions

Problem 27PE: (a) Ear trumpets were never very common, but they did aid people with hearing losses by gathering...

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Concept explainers

Stretched string

A stretched string is a wire which is made up of any metal that must have a larger length compared to its thickness. The ends of the wire are fixed, and when they oscillate or are plucked, it produces two reflected transverse waves of the same frequency and same amplitude. The waves or pulses are traveling in alternate directions and superimpose with one another. This waveform is named standing or stationary waves.

Question

The reverberation time is 1.2 s for a room with
dimensions of 6 m (L) x 4 m (W) x 3 m (H). What is
the additional sound absorption area required to
reduce the reverberation time to 1 s? Correct the
final answer to 2 decimal places.
Select one:
a. 0.85 m2
b. 1.93 m2
c. 2.29 m2
d. 3.52 m2

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Step 1: Formula for reverberation time

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Step 2 : Finding the sound absorption area when reverberation time is 1.2 second

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Step 3 : Calculating additional sound absorption area required to reduce reverberation time to 1sec

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Step 4: Calculating additional sound absorption area

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Step 5 : Conclusion

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