The shallow foundation shown below measures 2 m x 3 m and is subjected to a centric load and amoment. If eg = 0.2 m, ez = 0.3 m, and the depth of foundation is 1 m, determine the allowable load thefoundation can carry. Use a factor of safety of 3. For the soil, we are told that the unit weight, y = 17kn/m³, friction angle o' = 30°, and the cohesion, c' = 0.QultB× LQulteLQultQaln MyB

Solution: Shallow foundation measure=2×3 meB=0.2 meL=0.3 mdepth of foundation=30°Factor of…

The shallow foundation shown below measures 2 m x 3 m and is subjected to a centric load and a noment. If eg = 0.2 m, ei = 0.3 m, and the depth of foundation is 1 m, determine the allowable load the oundation can carry. Use a factor of safety of 3. For the soil, we are told that the unit weight, y = 17 kn/m², friction angle o' = 30°, and the cohesion, c' = 0.

The shallow foundation shown below measures 2 m x 3 m and is subjected to a centric load and a noment. If eg = 0.2 m, ei = 0.3 m, and the depth of foundation is 1 m, determine the allowable load the oundation can carry. Use a factor of safety of 3. For the soil, we are told that the unit weight, y = 17 kn/m², friction angle o' = 30°, and the cohesion, c' = 0.

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter6: Shallow Foundations: Ultimate Bearing Capacity

Section: Chapter Questions

Problem 6.21P: Consider a continuous foundation of width B = 1.4 m on a sand deposit with c = 0, = 38, and = 17.5...

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A square shallow foundation (B × B) is planned to be constructed on a normality consolidated (NC) clay soil as shown in the below figure. The maximum acceptable settlement for the foundation is equal to 2.0 inches (5 cm), and the safety factor against bearing capacity is FS = 4. Determine the size of foundation. (Note: To simplify the calculations, ignore both the elastic settlement and secondary compression settlement. Also consider Ao'ave = 4o'm) Q = 500 kN Ysat = 19.24 kN/m³ eo = 0.8 C. = 0.25 p'= 0 c' = 25 kPa FS again Bearing Capacity = 4 Acceptable settlement = 2.0 inches 2 m В ХВ 10 m
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