The solution to the equation 2 sin0 = -√3, where 0° <0<270°, to the nearest degree, is O-120° -240° 210° 240°

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.2: Trigonometric Equations
Problem 57E
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The solution to the equation 2 sin0 = -√3, where 0° < 0 < 270°, to the nearest degree, is
O-120°
O-240°
2 210°
O 240°
Transcribed Image Text:The solution to the equation 2 sin0 = -√3, where 0° < 0 < 270°, to the nearest degree, is O-120° O-240° 2 210° O 240°
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