The specific rotation of (S)-2-butanol is +135 IF100 g of its enantiomer is dissolved in 100 ml of ethanol and placed in a sample cell with a length of 1.00 dm, what observed rotation do you expect? 0 (-13.5N0.100g/mL(1.00dm) --135 O (13.510 100g/m(1.00dm] = 135 0 (-135/10.100gml}{1.00dm] = -135 O (135)0.100g/mL(1.00dm) 135
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- Thalidomide exists in two enantiomeric isomers as shown below. N (R) NI(S) O If a solution is prepared by adding a 50:50 ratio of two enantiomers what will be the expected observed rotation? Explain your answer in 1-2 sentences.The specific rotation of (S) butanol is +13.5 if 1.00g of its enantiomer is dissolved in 10.0mL of ethanol and placed in a sample cell with a length of 1.00 dm, what observed rotation do you expect?When 0.018 g of cholesterol is dissolved in 1.00 mL of ether and placed in a sample cell 10.0 cm in length, the observed rotation at 20 degrees (Using the D line of sodium) is -0.0567 degrees. Calculate the specific rotation of cholesterol. specific rotation= [α] =
- When 0.066 g of cholesterol is dissolved in 1.00 mL of ether and placed in a sample cell 10.0 cm in length, the observed rotation 20°C (using the D line of sodium) is -0.208°Calculate the specific rotation of cholesterol. specific rotation [a] = i eTextbook and Media6. a. The specific rotation of (S)-2-Chlorobutane in ethanol is +21.3°. A solution of the compound in a 10 cm tube has an observed rotation of [a] = 55°. What is the concentration of the compound in grams per 100 mL? b. Draw the structures of the following compounds (S)-2-Fluoropentane i. ii. (R)-3-lodo-2-methylpentaneSpecific rotation, [a]p of (S)-2-butanol at 25°C is +13,52°. Enantiomeric excess (%ees) of a mixture of (R)-2-butanol and (S)-2-butanol having specific rotation of + 6.76° at 25°C is Select one: O A. 60% O B. 50% O C. 20% O D. 75%
- The specific rotation of (R)-2-chlorobutane is -9.0 degrees. If 2.92 g of its enantiomer is dissolved in 6 mL of ether and placed in a sample cell with a length of 1.0 dm, what observed rotation do you expect (write answer with two decimal places)?A sample mixture containing the made-up enantiomers (R)-(+)-Nenamide and (S)-(-)-Nenamide has an apparent specific rotation of +6.50° at 25 °C. This sample has an enantiomeric excess (EE) of 43.0%. Provide answers to the following questions : 1.Which enantiomer is in excess in the sample? 2.What is the specific rotation of (S)-(-)-Nenamide?Me/H 3.8 Me/Me 15.5 You are trying to determine the optical purity (% enantiomeric excess) of a compound that you have just synthesized. You measure the rotation of plane-polarized light of a 0.5 g/mL solution and find the rotation to be +16.2 degrees (clockwise). Given the pure (-) isomer has a specific rotation of -45 degrees, what is the optical purity of the compound? Show, work. your
- 8. The specific rotation of (S)-carvone (at +20°C) is +61. A chemist prepared a mixture of (R)-carvone and its enantiomer, and this mixture had an observed rotation of -55°. (a) What is the specific rotation of (R)-carvone at 20°C? (b) Calculate the % ee of this mixture. (c) What percentage of the mixture is (S)-carvone?Note: enantiomers have similar physical properties (mp, density, solubility), and same [a], but with different signs ( - or +). Practice: 1.2 gm sample of cocaine, [a], = -16º, was dissolved in 7.5 mL of chloroform and placed in a sample tube having a pathlength of 5 cm. what was the observed rotation in degrees?(S)-carvone is an optically active compound with a specific rotation of +61.1°. A solution of carvone stereoisomers has an observed specific rotation of 25.0°. 1 Calculate the percent enantiomeric excess (%ee) of this mixture. 4 7 +/- 2 Question 1 of 2 5 8 %ee 3 6 9 0 Submit Tap here or pull up for additional resources ||| Г Xx C x 100