The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR, to find how the current I is changing at the moment when R = 442 Ω, I = 0.01 A, dv/dt = -0.05 V/s, and dR/dt = 0.08 2/s. (Round your answer to six decimal places.) A/s
The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's Law, V = IR, to find how the current I is changing at the moment when R = 442 Ω, I = 0.01 A, dv/dt = -0.05 V/s, and dR/dt = 0.08 2/s. (Round your answer to six decimal places.) A/s
Chapter3: Polynomial Functions
Section3.5: Mathematical Modeling And Variation
Problem 6ECP: The resistance of a copper wire carrying an electrical current is directly proportional to its...
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Transcribed Image Text:The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as
the resistor heats up. Use Ohm's Law, V = IR, to find how the current I is changing at the moment when R = 442 Ω,
I = 0.01 A, dv/dt = -0.05 V/s, and dR/dt = 0.08 2/s. (Round your answer to six decimal places.)
A/s
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