The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m. (1) If the datum for gravitational potential energy is set as shown below, the the gravitational potential energy of the wheel at the state 1 is 0 N m(two decimal places) (ANSWER IS 0) (2) If the datum for gravitional potential energ is set as shown below, the gravitational potential energy of the wheel at the state 2 is 0 N m (two decimal places) (ANSWER IS 0) (3) At state 1, how long the spring is stretched from its unstretched state (length difference):________(m) (two decimal places) (4) The elastic potential energy of the spring at the potion 1 is_______(N·m) (two decimal places) (5)  At state 2, how long the spring is stretched from its unstretched state (length difference):________(m) (two decimal places) (6) The elastic potential energy of the spring at the state 2 is_______(N·m) (two decimal places)  (7) The instantaneous center of zero velocity (IC) of the wheel at state 1 is (ANSWER IS POINT A) (8) The mass moment of inertial of the wheel about its mass center G is IG =_________(kg·m2 ) (two decimal places) (9) The mass moment of inertial of the wheel about its IC center at state 1 is IIC =_________(kg·m2 ) (two decimal places) (10) The total kinetic energy of the system at the state1 is:________ (N·m) (two decimal places) (11) Apply the theory of work-energy  to the whole system during state 1 and state 2, and calculate the angular velocity of the wheel at the state 2:  2 rad/s. (two decimal places)  (ANSWER IS 2 rad/s) 12) Based on result from (11), the kinetic energy of the wheel at the state 2 is:______ (N·m) (two decimal places)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Please answer: 3, 4, 5, 6, 8, 9, 10, 12

 

The wheel is attached to the spring. The mass of the wheel is m=20 kg. The radius of the wheel is 0.6m. The radius of gyration kG=0.4 m. The spring’s unstretched length is L0=1.0 m. The stiffness coefficient of the spring is k=2.0 N/m. The wheel is released from rest at the state 1 when the angle between the spring and the vertical direction is θ=30°. The wheel rolls without slipping and passes the position at the state 2 when the angle is θ=0°. The spring’s length at the state 2 is L2=4 m.

(1) If the datum for gravitational potential energy is set as shown below, the the gravitational potential energy of the wheel at the state 1 is 0 N m(two decimal places) (ANSWER IS 0)

(2) If the datum for gravitional potential energ is set as shown below, the gravitational potential energy of the wheel at the state 2 is 0 N m (two decimal places) (ANSWER IS 0)

(3) At state 1, how long the spring is stretched from its unstretched state (length difference):________(m) (two decimal places)

(4) The elastic potential energy of the spring at the potion 1 is_______(N·m) (two decimal places)

(5)  At state 2, how long the spring is stretched from its unstretched state (length difference):________(m) (two decimal places)

(6) The elastic potential energy of the spring at the state 2 is_______(N·m) (two decimal places) 

(7) The instantaneous center of zero velocity (IC) of the wheel at state 1 is (ANSWER IS POINT A)

(8) The mass moment of inertial of the wheel about its mass center G is I=_________(kg·m) (two decimal places)

(9) The mass moment of inertial of the wheel about its IC center at state 1 is IIC =_________(kg·m) (two decimal places)

(10) The total kinetic energy of the system at the state1 is:________ (N·m) (two decimal places)

(11) Apply the theory of work-energy  to the whole system during state 1 and state 2, and calculate the angular velocity of the wheel at the state 2:  2 rad/s. (two decimal places)  (ANSWER IS 2 rad/s)

12) Based on result from (11), the kinetic energy of the wheel at the state 2 is:______ (N·m) (two decimal places)

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Transcribed Image Text:// 44 L2 J- State 2 Li State 1 datum
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