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three textbox arrays A1, A2, A3 contains degrees of 10 stu * three materials. The code to find the average of each st Fori=0 to 9 For i=0 to 9 S=(val(A1(i).text)+ val(A2(i S=S+(val(A(i).text)/3 |val(A3(i).text))/3 Form1.print S Form1.printS Nexti Nexti the Code is C The cc Fori=0 to 9 For i 0 to 9 S=S+(val(A(i).tex S=S+(val(A1(i).text)+ val(A2(i).text)+ |val(A3(i).text))/3 Form1.print S Form1.printS Nexti Nexti Av=S/3

three textbox arrays A1, A2, A3 contains degrees of 10 stu * three materials. The code to find the average of each st Fori=0 to 9 For i=0 to 9 S=(val(A1(i).text)+ val(A2(i S=S+(val(A(i).text)/3 |val(A3(i).text))/3 Form1.print S Form1.printS Nexti Nexti the Code is C The cc Fori=0 to 9 For i 0 to 9 S=S+(val(A(i).tex S=S+(val(A1(i).text)+ val(A2(i).text)+ |val(A3(i).text))/3 Form1.print S Form1.printS Nexti Nexti Av=S/3

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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three textbox arrays A1, A2, A3 contains degrees of 10 students in * three materials. The code to find the average of each student is blä 5 Fori=0 to 9 For i=0 to 9 S={val(A1(i).text)+ val(A2(i).text)+ S=S+(val(A(i).text)/3 |val(A3(i).text))/3 Form1.print S Form1.printS Nexti Nexti the Code is The code is Fori=0 to 9 For i=0 to 9 S=S+(val(A(i).text) S=S+(val(A1(i).text)+ val(A2(i).text)+ |val(A3(i).text))/3 Form1.print S Form1.printS Nexti Nexti Av=S/3 the code is The Code is
Transcribed Image Text:three textbox arrays A1, A2, A3 contains degrees of 10 students in * three materials. The code to find the average of each student is blä 5 Fori=0 to 9 For i=0 to 9 S={val(A1(i).text)+ val(A2(i).text)+ S=S+(val(A(i).text)/3 |val(A3(i).text))/3 Form1.print S Form1.printS Nexti Nexti the Code is The code is Fori=0 to 9 For i=0 to 9 S=S+(val(A(i).text) S=S+(val(A1(i).text)+ val(A2(i).text)+ |val(A3(i).text))/3 Form1.print S Form1.printS Nexti Nexti Av=S/3 the code is The Code is
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