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TRUE OR FALSE:
- If there is a past estimation error, there is a need to replace the property immediately.
- The physical life is always greater than all the other “life” factors under replacement analysis.
- If breakeven analysis is conducted with PW analysis for different MEAs, it doesn’t guarantee that the fastest
alternative to reach its breakeven point has also the highest equivalent worth.
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- A theft-avoidance locking system has a first cost of $23,500, an AOC of $16,000, and no salvage value after its 3-year life. Assume that you were told the service provided by this asset would be needed for only 5 years. This means that the asset will have to be repurchased and kept for only 2 years. What would its market value, call it M, have to be after 2 years in order to make its annual worth the same as it is for its 3-year life cycle at an interest rate of 10% per year? Determine the market value M using factors. The market value M is $Polypropylene wall caps, used for covering exterior vents for kitchen cooktops. bathroom fans, dryers, and other building air exhausts. can be made by two different methods. Method X will have a first cost of $75,000. an operating cost of $32,000 per year, and a $9000 salvage value after 4 years. Method Y will have a first cost of $140,000. an operating cost of $24,000 per year, and a $19,000 salvage value after its 4-year life. At an interest rate of 10% per year, which method should be used on the basis of an annual worth analysis? 10% TABLE 15 Discrete Cash Flow: Compound interest Factors 10% Single Payments Uniform Series Payments Arithmetic Gradients Compound Amount Capital Recovery Present Sinking Fund Compound Amount Present Gradient Gradient Worth Worth Present Worth Uniform Series F/P P/F A/F F/A A/P P/A P/G A/G L1000 110000 0.9091 09091 08264 10000 0.47619 0.30211 10000 04762 0.9366 12100 21000 0.57619 0.40211 1.7355 13310 0.7513 3.3100 2.4869 23291 14641 06830 0.21547 4,6410…TRUE OR FALSE 4. If there is a past estimation error, there is a need to replace the property immediately.5. The physical life is always greater than all the other “life” factors under replacement analysis.6. If breakeven analysis is conducted with PW analysis for different MEAs, it doesn’t guarantee that the fastestalternative to reach its breakeven point has also the highest equivalent worth.
- To produce an item in-house, equipment costing $250,000 must be purchased. It will have a life of 4 years and an annual cost of $80,000; each unit will cost $40 to manufacture. Buying the item externally will cost $100 per unit. At i = 12%, determine the breakeven production number.No written by hand solution An electric switch manufacturing company is trying to decide between three different assembly methods. Method A has an estimated first cost of $30,000, an annual operating cost (AOC) of $4,000, and a service life of 2 years. Method B will cost $70,000 to buy and will have an AOC of $3,000 over its 4-year service life. Method C costs $115,000 initially with an AOC of $3,000 over its 8-year life. Methods A and B will have no salvage value, but Method C will have equipment worth 6% of its first cost.An industrial machine costing $10,000 will produce net cash savings of $4,000 per year. The machine has a five-year useful life but must be returned to the factory for major repairs after three years of operation. These repairs cost $5,000. The company's MARR is 10% per year. What IRR will be earned on the purchase of this machine? Analyze the sensitivity of IRR to $2,000 changes in the repair cost. Perform the sensitivity analysis. Fill-in the table below. (Round to one decimal place.) Change in the repair cost - $2,000 $0 IRR 21.05% % Is the project acceptable? Yes
- NEED HELP ASAP!! THANK YOU! Two processes can be used for producing a new engine. Process A will have a first cost of P750,000, an operating cost of P60,000 per year, and a salvage value of P80,000 after its 2-year life. Process B will have a first cost of P1,350,000, an operating cost of P25,000 per year, and a P120,000 salvage value after its 4-year life. Process B will also require updating at the end of year 2 at a cost of P90,000. On the basis of a future worth analysis at an interest rate of 12% per year, write the ANSWER for ALTERNATIVE A: Blank 1 ANSWER for ALTERNATIVE B: Blank 2An independent contractor for a transportation company needs to determine whether she should upgrade the vehicle she currently owns or trade her vehicle in to lease a new vehicle. If she keeps her vehicle, she will need to invest in immediate upgrades that cost $4,700 and it will cost $1,450 per year to operate at the end of year that follows. She will keep the vehicle for 6 years; at the end of thi period, the upgraded vehicle will have a salvage value of $4,300. Alternatively, she could trade in her vehicle to lease a new vehicle. Sh estimates that her current vehicle has a trade-in value of $9.300 and that there will be $4,500 due at lease signing. She further estimates that it will cost $3,300 per year to lease and operate the vehicle. The independent contractor's MARR is 12%. Compute the EUAC of both the upgrade and lease alternatives using the insider perspective. Click here to access the TVM Factor Table Calculator. EUAC(keep): EUAC(lease): $ S Carry all interim calculations to…An asset was purchased 5 years ago at a price of $52,000. It was expected to be in service for 8 years, at which time its salvage value would be $4000. If the function that the asset was serving is no longer, what price must it be sold to recover the invested capital when i = 12%
- The Bureau of Public Highways is considering two possible types of road surfacing with cost estimates per kilometer as follows: Type A Type B First Cost P500k P650k Resurfacing period 8 years 12 years Resurfacing Cost P200k P250k Average annual maintenance cost P15k P20k The periodic resurfacing do not include the base of the subgrade. Compare these types by calculating the present worth for 24 year service, with no salvage value at the end of this time using interest rate of 10%. What is the Present Worth of Alternative B?5. The physical life is always greater than all the other "life" factors under replacement analysis. 6. If breakeven analysis is conducted with PW analysis for different MEAS, it doesn't guarantee that the fastest alternative to reach its breakeven point has also the highest equivalent worth.A remotely located air sampling station can be powered by solar cells or by running an above ground electric line to the site and using conventional power. Solar cells will cost $16,600 to install and will have a useful life of 5 years with no salvage value. Annual costs for inspection, cleaning, etc., are expected to be $2400. A new power line will cost $31,000 to install, with power costs expected to be $1000 per year. Since the air sampling project will end in 5 years, the salvage value of the line is considered to be zero. At an interest rate of 10% per year, (b) what must be the first cost of the above ground line to make the two alternatives equally attractive economically?