Tutorial Exercise Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 16.0 cm and b = 32.0 cm. 12.0 N 30.0% = 10.0 N 9.00 N Step 1 The total torque on an object is the sum of the individual torques. Remember that d is the perpendicular distance from the rotation axis to the line of action of the force F, called the moment arm or lever arm of F. We have the following. ΣT=Fd N)(0.32 m) N)(0.16 m)-(10.0 N)(1 N m e m This represents a torque vector that points into the plane of the page, and results in a counterclockwise turning by the force.

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Chapter1: Units, Trigonometry. And Vectors
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Tutorial Exercise
Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking
a = 16.0 cm and b = 32.0 cm.
12.0 N
=
30.0
=
10.0 N
Step 1
The total torque on an object is the sum of the individual torques. Remember that d is the perpendicular distance from
the rotation axis to the line of action of the force F, called the moment arm or lever arm of F. We have the following.
ΣT=Fd
N)(0.32 m)
This represents a torque vector that points into the plane of the page, and results in a counterclockwise turning by
the force.
9.00 N
N)(0.16 m) -(10.0 N)
N m
m
n) - (C
Transcribed Image Text:Tutorial Exercise Find the net torque on the wheel in the figure below about the axle through O perpendicular to the page, taking a = 16.0 cm and b = 32.0 cm. 12.0 N = 30.0 = 10.0 N Step 1 The total torque on an object is the sum of the individual torques. Remember that d is the perpendicular distance from the rotation axis to the line of action of the force F, called the moment arm or lever arm of F. We have the following. ΣT=Fd N)(0.32 m) This represents a torque vector that points into the plane of the page, and results in a counterclockwise turning by the force. 9.00 N N)(0.16 m) -(10.0 N) N m m n) - (C
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