Two blocks are tied together with a massless string that does not stretch and connected via a frictionless and massless pulley. Mass one, M1, rests on a table top and is stationary. Denote the force for static friction as Fs and the tension in the string by T. M,
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A: Given: m1=4 kgm2=5 kg The free-body diagram is given below.
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A: GivenF1=120 N , θ1=60°ansF2=80 N , θ2=75°
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A: Condition for static equilibrium T-fs=0m2g-μsN1=0m2g-μsm1g=0μs=m2m1
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- A horizontal force F pushes against a block of mass m. The mass m in turn pushes against a bigger block of mass M. There isn't friction any between the larger block and the table, but there is friction in between the blocks (coef. of static friction is μs). What's the smallest force F that will hold the smaller mass m m against the larger mass M without letting the smaller mass m fall down?Two blocks of mass Mj and M2 are connected by a massless string that passes over a massless pulley as shown in the figure. M, has a mass of 2.75 kg and rests on an incline of 0, = 63.5°. M2 rests on an incline of 02 = 17.5°. Find the mass of block M, so that the system is in equilibrium (i.e., M2 not accelerating). All surfaces are frictionless. kg M2 Figure is not to scale.Two blocks of mass M1 and M2 are connected by a massless string that passes over a massless pulley as shown in the figure. M1 has a mass of 8.75 kg and rests on an incline of M2 01 = 63.5°. M2 rests on an incline of 02 33.5°. Find the %3D M, mass of block M2 so that the system is in equilibrium (i.e., not accelerating). All surfaces are frictionless. 0, Figure is not to scale. kg M2 =
- Two blocks of mass M1 and M2 are connected by a massless string that passes over a massless pulley as shown in the figure. M1 has a mass of 6.75 kg and rests on an incline of 01 = 65.5°. M2 rests on an incline of 02 = 35.5°. Find the mass of block M2 so that the system is in equilibrium (i.e., not accelerating). All surfaces are frictionless. 0, M2 = kg Figure is not to scale.A horizontal force P of 379 N is applied on the crate of weight W=870 N. Initially the crate is left motionless. Find the magnitude and direction of friction force that are applied by the flat surface on the crate. Take the value of coefficient of static friction as 0.47 and the value of coefficient of kinetic friction as 0.33. a. ) The magnitude of friction force is 322 N and it is acting in the direction b. ) The magnitude of friction force is 379 N and it is acting in the direction c. ) The magnitude of friction force is 322 N and it is acting in the direction d.) The magnitude of friction force is 379 N and it is acting in the directionA body of weight w is attached by a string of length L, to a hook on a vertical wall. A horizontal force F acting on the body holds it at a distance d from the wall. Derive the equation, which gives the force F in terms of w, L, and d.
- An object with mass (M1= 8 Kg) rests on a rough horizontal table and is connected by a cable that passes over a pulley (massless and frictionless) and is then tied to a hanging object with mass (M2=7 kg). As shown in the figure below. The coefficient of kinetic friction between block M1 and the surface is 0.16 (a) Find the acceleration of each object and (b) Tension in the cable. M, M,Mass Ma lies on top of mass Mb, as shown. Assume Mb > Ma. The two blocks are pulled from rest by a massless rope passing over a pulley. The pulley is accelerated at rate A. Block Mb slides on the table without friction, but there is a constant friction force f between Ma and Mb due to their relative motion. Find the tension in the rope.Objects with masses m₁ = 11.0 kg and m₂ = 6.0 kg are connected by a light string that passes over a frictionless pulley as in the figure below. If, when the system starts from rest, m₂ falls 1.00 m in 1.64 s, determine the coefficient of kinetic friction between m₁ and the table. 54.39 X Express the friction force in terms of the coefficient of kinetic friction. Obtain an expression for the acceleration in terms of the masses and the net force, including friction, and solve for the coefficient of kinetic friction. m1 m₂
- A mug of root beer is sliding across a horizontal table with a constant velocity of 5.0[m/s], and is experiencing a friction force. If the mug has a total mass of 2.60[kg] and μk = 0.250, find the force due to friction. Express your answer in N.A 2.78 kg mass is sliding across a horizontal surface while being pushed on by an applied force of 19.3 N i. If the acceleration of the mass is 3.71 m/s? i, what is the magnitude of force of kinetic friction acting on the mass as it slides? Enter a number with 2 decimal places and assume it has proper SI Units and is directed in the -i direction.Sasha is dragging some hockey equipment across the ice rink. The equipment (object 1) has a mass of 75.0[kg] and has another piece of equipment (object 2) with a mass of 35.0[kg] tethered to it. She pulls on the rope she is holding so that it has a tension of 783[N] and it makes an angle of 30o with respect to the horizontal direction. Friction is negligible. Find the magnitude of the tension in the cord connecting the two objects. Express your answer in units of N.