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Two countries have a high number of 10 year old soccer players. A Mathematician is curious to see if country 1 soccer players has a mass less than country 2 soccer players. He recorded the following samples (in pounds): Country 2 69.6, 70.3, 70, 70.5, 71.5, 72.8, 71.1, 69, 70.6, 70.6, 71.1, 71.5 X₁ = Country 1 64, 62.7, 65.8, 61.8, 64.8, 66.8, 63.3, 61.8, 66.6, 67.2 S₁ = , X₂ = , S₂ = Assuming that the population variances are not equal, construct a 90 percent confidence interval: Degrees of Freedom = Σμη - με Use the a=0.1 significance level to test the claim that the mean weight in Country 1 is less than in Country 2 (again, assume the variances are not equal). Select the correct null and alternative hypotheses: OA.Ho:-1-|2=0,HA:-1 - M270 OB. Ho 1₂ = 0,HA 1-₂ > 0 OC. Ho M1 M2=0,HA M₁ M₂ <0 OD. None of the above The rejection region for this test is: OA. (1.35622, ∞) OB. (-∞, -1.35622) U (1.35622,00) OC. (-∞, -1.35622) OD. (1.78229, ∞) OE. (-∞, -1.78229) OF. (-∞, -1.78229) U (1.78229, ∞0) OG. None of the above The conclusion is: The test statistic is t = OA. There is sufficient evidence to support the claim that weights of the soccer

Two countries have a high number of 10 year old soccer players. A Mathematician is curious to see if country 1 soccer players has a mass less than country 2 soccer players. He recorded the following samples (in pounds): Country 2 69.6, 70.3, 70, 70.5, 71.5, 72.8, 71.1, 69, 70.6, 70.6, 71.1, 71.5 X₁ = Country 1 64, 62.7, 65.8, 61.8, 64.8, 66.8, 63.3, 61.8, 66.6, 67.2 S₁ = , X₂ = , S₂ = Assuming that the population variances are not equal, construct a 90 percent confidence interval: Degrees of Freedom = Σμη - με Use the a=0.1 significance level to test the claim that the mean weight in Country 1 is less than in Country 2 (again, assume the variances are not equal). Select the correct null and alternative hypotheses: OA.Ho:-1-|2=0,HA:-1 - M270 OB. Ho 1₂ = 0,HA 1-₂ > 0 OC. Ho M1 M2=0,HA M₁ M₂ <0 OD. None of the above The rejection region for this test is: OA. (1.35622, ∞) OB. (-∞, -1.35622) U (1.35622,00) OC. (-∞, -1.35622) OD. (1.78229, ∞) OE. (-∞, -1.78229) OF. (-∞, -1.78229) U (1.78229, ∞0) OG. None of the above The conclusion is: The test statistic is t = OA. There is sufficient evidence to support the claim that weights of the soccer

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.4: Collecting Data
Problem 3E
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Use the a = 0.1 significance level to test the claim that the mean weight in Country 1 is less than in Country 2 (again, assume the variances are not equal). Select the correct null and alternative hypotheses: Α. Η : μι – μ2 = 0,HA : μι – με 7 0 ) Β. Η : μι – μ2 = 0,HA : μι – μ2 > 0 C. Ho :/1 μ₂ = 0,HA: M₁ - μ₂ < 0 D. None of the above - The rejection region for this test is: A. (1.35622, ∞) B. (-∞, -1.35622) U (1.35622, ∞) C. (-∞, -1.35622) D. (1.78229, ∞) E. (-∞, -1.78229) F. (-∞, -1.78229) U (1.78229, ∞) G. None of the above The test statistic is t The conclusion is: OA. There is sufficient evidence to support the claim that weights of the soccer players from country 1 is less than country 2 B. There is not sufficient evidence to support the claim that weights of the soccer players from country 1 is less than country 2
Transcribed Image Text:Use the a = 0.1 significance level to test the claim that the mean weight in Country 1 is less than in Country 2 (again, assume the variances are not equal). Select the correct null and alternative hypotheses: Α. Η : μι – μ2 = 0,HA : μι – με 7 0 ) Β. Η : μι – μ2 = 0,HA : μι – μ2 > 0 C. Ho :/1 μ₂ = 0,HA: M₁ - μ₂ < 0 D. None of the above - The rejection region for this test is: A. (1.35622, ∞) B. (-∞, -1.35622) U (1.35622, ∞) C. (-∞, -1.35622) D. (1.78229, ∞) E. (-∞, -1.78229) F. (-∞, -1.78229) U (1.78229, ∞) G. None of the above The test statistic is t The conclusion is: OA. There is sufficient evidence to support the claim that weights of the soccer players from country 1 is less than country 2 B. There is not sufficient evidence to support the claim that weights of the soccer players from country 1 is less than country 2
Two countries have a high number of 10 year old soccer players. A Mathematician is curious to see if country 1 soccer players has a mass less than country 2 soccer players. He recorded the following samples (in pounds): X₁ = S₁ = Country 1 64, 62.7, 65.8, 61.8, 64.8, 66.8, 63.3, 61.8, 66.6, 67.2 Country 2 69.6, 70.3, 70, 70.5, 71.5, 72.8, 71.1, 69, 70.6, 70.6, 71.1, 71.5 , X₂ = , S₂ = Assuming that the population variances are not equal, construct a 90 percent confidence interval: Degrees of Freedom = Σμι - με Σ Use the a = 0.1 significance level to test the claim that the mean weight in Country 1 is less than in Country 2 (again, assume the variances are not equal). Select the correct null and alternative hypotheses: Ο Α. Η : μη – με = 0,HA : μι - με 7 0 OB. Ho: ₁ - ₂ = 0,HA M₁ M₂ > 0 Ο c. H : μι – με = 0,HA : μι – με < 0 OD. None of the above The rejection region for this test is: OA. (1.35622, ∞) OB. (-∞, -1.35622) U (1.35622, ∞0) OC. (-∞, -1.35622) D. (1.78229, ∞) E. (-∞, -1.78229) OF. (-∞, -1.78229) U (1.78229, ∞) OG. None of the above The conclusion is: The test statistic is t = A. There is sufficient evidence to a aim that weights of the soccer
Transcribed Image Text:Two countries have a high number of 10 year old soccer players. A Mathematician is curious to see if country 1 soccer players has a mass less than country 2 soccer players. He recorded the following samples (in pounds): X₁ = S₁ = Country 1 64, 62.7, 65.8, 61.8, 64.8, 66.8, 63.3, 61.8, 66.6, 67.2 Country 2 69.6, 70.3, 70, 70.5, 71.5, 72.8, 71.1, 69, 70.6, 70.6, 71.1, 71.5 , X₂ = , S₂ = Assuming that the population variances are not equal, construct a 90 percent confidence interval: Degrees of Freedom = Σμι - με Σ Use the a = 0.1 significance level to test the claim that the mean weight in Country 1 is less than in Country 2 (again, assume the variances are not equal). Select the correct null and alternative hypotheses: Ο Α. Η : μη – με = 0,HA : μι - με 7 0 OB. Ho: ₁ - ₂ = 0,HA M₁ M₂ > 0 Ο c. H : μι – με = 0,HA : μι – με < 0 OD. None of the above The rejection region for this test is: OA. (1.35622, ∞) OB. (-∞, -1.35622) U (1.35622, ∞0) OC. (-∞, -1.35622) D. (1.78229, ∞) E. (-∞, -1.78229) OF. (-∞, -1.78229) U (1.78229, ∞) OG. None of the above The conclusion is: The test statistic is t = A. There is sufficient evidence to a aim that weights of the soccer
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