Two forces, F, = (-5.80î – 3.95j) N andF, = (-3.70î - 5.95j) N, act on a particle of mass 2.30 kg that is initially at rest at coordinates (+2.25 m, +4.40 m).(a) What are the components of the particle's velocity at t = 11.1 s?m/s(b) In what direction is the particle moving at t = 11.1 s?o counterclockwise from the +x-axis(c) What displacement does the particle undergo during the first 11.1 s?AT =m(d) What are the coordinates of the particle at t = 11.1 s?y =

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Answered: Two forces, F, = (-5.80î – 3.95j) N and…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Two forces, F1 = (6.10î + 4.30ĵ) N and F2 = (3.40î + 7.65ĵ) N, act on a particle of mass 2.20 kg that is initially at rest at coordinates (+2.05 m, −4.50 m). (a) What are the components of the particle's velocity at t = 10.7 s? v= (in m/s)
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Two forces, F :(-4.00î – 3.95ĵ) N and F, = (-3.95î – 4.95j) N, act on a particle of mass 1.90 kg that is initially at rest at 1 coordinates (+1.95 m, +4.05 m). (a) What are the components of the particle's velocity at t = 11.1 s? m/s (b) In what direction is the particle moving at t = 11.1 s? ° counterclockwise from the +x-axis (c) What displacement does the particle undergo during the first 11.1 s? (d) What are the coordinates of the particle at t = 11.1 s? X = m y =
Two forces, F, = (2.70î – 3.40j) N and F, = (3.70î – 7.80j) N, act on a particle of mass 2.10 kg that is initially at rest at coordinates (-1.50 m, +4.40 m). 1 (b) In what direction is the particle moving at t = 11.5 s? ° counterclockwise from the +x-axis
A pendulum consists of a 2 kg bob attached to a light string of length 6.0 m. The bob is struck horizontally so that it has an initial horizontal velocity of 3.0 m/s. What is the angle of the string with the vertical when the bob reaches its maximum height?
Two forces, F1 = (6.10î + 4.30ĵ) N and F2 = (3.40î + 7.65ĵ) N, act on a particle of mass 2.20 kg that is initially at rest at coordinates (+2.05 m, −4.50 m). (b) In what direction is the particle moving at t = 10.7 s? (answer in ° counterclockwise from the +x-axis)
A 1.68 kg mass is initially at rest upon a frictionless, horizontal surface. An applied force of 9.13 N i then acts on the mass for 3.72 seconds. What is the speed of the mass when the applied force stops acting?
The mass of particle 1 is 11kg. The initial velocity for particle 1 is (-104m/s)i + (216m/s)j. F21 = Fxe^-(t/T) + Fysin(2pit/T). Only need help finding the displacement of particle 1 in the x and y directions.
Two forces, F1 = (3.90î − 2.60ĵ) N and F2 = (3.65î − 8.05ĵ) N, act on a particle of mass 2.10 kg that is initially at rest at coordinates (+1.60 m, +3.50 m). (a) What are the components of the particle's velocity at t = 11.8 s? v = 42.362i−59.826j m/s (b) In what direction is the particle moving at t = 11.8 s? 305.30 2 (c) What displacement does the particle undergo during the first 11.8 s?Δr = 863.07 m is not correct answer (d) What are the coordinates of the particle at t = 11.8 s? x = 249 m y = -713.5 m is not correct answer Please give correct, complete, and detailed formulas for correctly solving these questions.
A block of mass m1 =3 kg is on a table and attached to a block of mass m2 =4 kg m2 =4 kg by a mass less string. The coefficient of friction is 0.28 between the table and m1. The system is released from rest. After m2 falls 1.5 m,1.5 m, what is the speed of m2?

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