Under constant pressure P = 1 atm an ideal gas of 1.5 mol undergoes cooling from 120°C to 30.0°C, and CV,m = 3/2R. Please calculate q, w, AU, and AH (all units are J). Please enter all four answers using scientific notation (E notation) with three significant figures, such as 2.30E4 (=23000). If the answer is negative, please do not forget the negative sign. If answer is zero, please just enter O without decimal. (1) q= -2.81E3 (2) W= -1.12E3 (3) AU= -1.68E3 (4) AH= -2.81E3

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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QUESTION 2
Under constant pressure P = 1 atm an ideal gas of 1.5 mol undergoes cooling from 120°C to
30.0°C, and CV,m = 3/2R. Please calculate q, w, AU, and AH (all units are J).
Please enter all four answers using scientific notation (E notation) with three significant figures,
such as 2.30E4 (=23000). If the answer is negative, please do not forget the negative sign. If
answer is zero, please just enter 0 without decimal.
(1) q= -2.81E3
(2) w= -1.12E3
(3) AU= -1.68E3
(4) AH= -2.81E3
Transcribed Image Text:QUESTION 2 Under constant pressure P = 1 atm an ideal gas of 1.5 mol undergoes cooling from 120°C to 30.0°C, and CV,m = 3/2R. Please calculate q, w, AU, and AH (all units are J). Please enter all four answers using scientific notation (E notation) with three significant figures, such as 2.30E4 (=23000). If the answer is negative, please do not forget the negative sign. If answer is zero, please just enter 0 without decimal. (1) q= -2.81E3 (2) w= -1.12E3 (3) AU= -1.68E3 (4) AH= -2.81E3
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