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Use (20) in Section 6.4. 1 - 2a y" + + (b²c²x²c − 2 + 0² - p²c²)y ₁ X Find the general solution of the given differential equation on (0, ). (The definitions of various Bessel functions are given here.) xy" + 2y' + 9y = 0 ○ y(x) = x¹/² [C₁J₁ (3x −¹/2) + C₂Y₁(3x-¹/2)] Ⓒy(x) = x-¹/²[C₁³₁ (3x¹/2) + C₂Y₁(3x¹/2)] O y(x) = x-1/² [C₁J₁ (6x¹/2) + C₂Y₁(6x¹/2)] O y(x) = x-¹/² [C₁J₁ (3x¹/2) + C₂J_1(3x¹/2)] 1/2. -1/2. y = 0, p≥0 (20) -1/2..

Use (20) in Section 6.4. 1 - 2a y" + + (b²c²x²c − 2 + 0² - p²c²)y ₁ X Find the general solution of the given differential equation on (0, ). (The definitions of various Bessel functions are given here.) xy" + 2y' + 9y = 0 ○ y(x) = x¹/² [C₁J₁ (3x −¹/2) + C₂Y₁(3x-¹/2)] Ⓒy(x) = x-¹/²[C₁³₁ (3x¹/2) + C₂Y₁(3x¹/2)] O y(x) = x-1/² [C₁J₁ (6x¹/2) + C₂Y₁(6x¹/2)] O y(x) = x-¹/² [C₁J₁ (3x¹/2) + C₂J_1(3x¹/2)] 1/2. -1/2. y = 0, p≥0 (20) -1/2..

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 12CR
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Use (20) in Section 6.4. - y" + 1 − 2ªy' + (6²c²x²c − 2 + a² − p²c²), - X = 0, p≥ 0 (20) Find the general solution of the given differential equation on (0, ∞). (The definitions of various Bessel functions are given here.) xy" + 2y' + 9y = 0 O y(x) = x¹/²[C₁³₁(3x-¹/2) + C₂Y₁(3x-¹/2)] Ⓒ y(x) = x¯¹/²[C₁J₁ (3x¹/2) + C₂Y₁(3x¹/2)] O y(x) = x ¹/2[C₁J₁ (6x¹/2) + C₂Y₁(6x¹/2)] ○ y(x) = x-¹/²[C₁J₁ (3x¹/2) + C₂³_₁(3x¹/2)] ○ y(x) = x¹/²[C₁J₁(6x−1/2) + C₂Y₁(6x−¹/2)]
Transcribed Image Text:Use (20) in Section 6.4. - y" + 1 − 2ªy' + (6²c²x²c − 2 + a² − p²c²), - X = 0, p≥ 0 (20) Find the general solution of the given differential equation on (0, ∞). (The definitions of various Bessel functions are given here.) xy" + 2y' + 9y = 0 O y(x) = x¹/²[C₁³₁(3x-¹/2) + C₂Y₁(3x-¹/2)] Ⓒ y(x) = x¯¹/²[C₁J₁ (3x¹/2) + C₂Y₁(3x¹/2)] O y(x) = x ¹/2[C₁J₁ (6x¹/2) + C₂Y₁(6x¹/2)] ○ y(x) = x-¹/²[C₁J₁ (3x¹/2) + C₂³_₁(3x¹/2)] ○ y(x) = x¹/²[C₁J₁(6x−1/2) + C₂Y₁(6x−¹/2)]
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