Use the References to access important values if needed for this question. A sample of a substance with the empirical formula XCI₂ weighs 0.5351 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2478 g. The chemical reaction is XCl₂ + 2 AgNO3-2AgCl + X(NO3)2 (a) Calculate the formula mass of XCI₂. Formula mass XCl₂ = (b) Calculate the atomic mass of X. Atomic mass X= g mol-¹ g mol-1

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Chapter9: Chemical Quantities
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Use the References to access important values if needed for this question.
A sample of a substance with the empirical formula XCI₂ weighs 0.5351 g. When it is dissolved
in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver
nitrate, the mass of the resulting AgCl is found to be 1.2478 g. The chemical reaction is
XCI₂ + 2 AgNO32AgCl + X(NO3)2
(a) Calculate the formula mass of XCI₂.
Formula mass XCl₂ =
(b) Calculate the atomic mass of X.
Atomic mass X =
g mol-1
g mol-1
Transcribed Image Text:Use the References to access important values if needed for this question. A sample of a substance with the empirical formula XCI₂ weighs 0.5351 g. When it is dissolved in water and all its chlorine is converted to insoluble AgCl by addition of an excess of silver nitrate, the mass of the resulting AgCl is found to be 1.2478 g. The chemical reaction is XCI₂ + 2 AgNO32AgCl + X(NO3)2 (a) Calculate the formula mass of XCI₂. Formula mass XCl₂ = (b) Calculate the atomic mass of X. Atomic mass X = g mol-1 g mol-1
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