Use the References to access important values if needed for this question. For the reaction 2 H202(1) 2 H20(1) + O2(g) AG= -229.1 kd and AH -196.0 k) at 263 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 263 K. The entropy change for the reaction of 2.42 moles of H302(1) at this temperature would be /K. Submit Answer Try Another Version

Chemistry for Engineering Students
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Chapter10: Entropy And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 10.47PAE: The reaction CO2(g)+H2(g)CO(g)+H2O(g) is not spontaneous at room temperature but becomes spontaneous...
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Use the References to access important values if needed for
this question.
For the reaction
2 H202(1) 2 H30(1) + O2(g)
AG= -229.1 kd and AH -196.0 k) at 263 K and 1 atm.
This reaction is (reactant, product)
favored under
standard conditions at 263 K.
The entropy change for the reaction of 2.42 moles of H202(1)
at this temperature would be
/K.
Submit Answer
Try Another Version
Transcribed Image Text:Use the References to access important values if needed for this question. For the reaction 2 H202(1) 2 H30(1) + O2(g) AG= -229.1 kd and AH -196.0 k) at 263 K and 1 atm. This reaction is (reactant, product) favored under standard conditions at 263 K. The entropy change for the reaction of 2.42 moles of H202(1) at this temperature would be /K. Submit Answer Try Another Version
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