Use the van der Waals equation of state to calculate the pressure of 4.00 mol of SO, at 453K in a 3.80 L vessel. Van der Waals constants can be found in the van der Waals constants table. P = atm Use the ideal gas equation to cakulate the pressure under the same conditions. P= 39.15 atm
Use the van der Waals equation of state to calculate the pressure of 4.00 mol of SO, at 453K in a 3.80 L vessel. Van der Waals constants can be found in the van der Waals constants table. P = atm Use the ideal gas equation to cakulate the pressure under the same conditions. P= 39.15 atm
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter5: Gases
Section: Chapter Questions
Problem 78QAP
Related questions
Question
Transcribed Image Text:8:21 >4OB 00 •
83% i
00
Use the van der Waals equation of state to calculate the pressure of 4.00 mol of SO, at 453K in a 3.80 L vessel. Van der Waals
constants can be found in the van der Waals constants table.
Use the ideal gas equation to cakulate the pressure under the same conditions.
P =
39.15
atm
In a 16.80 L vessel, the pressure of 4.00 mol of SO, at 453 K is 8.85 atm when calculated using the ideal gas equation and
8.59 atm when calculated using the van der Waals equation of state.
II
Transcribed Image Text:8:22 >10 000 •
83% i
00
In a 16.80 L vessel, the pressure of 4.00 mol of SO, at 453 K is 8.85 atm when calkulated using the ideal gas equation and
8.59 atm when calculated using the van der Waals equation of state.
Why is the percent difference in the pressures calculated using the two different equations greater when the gas is in the
3.80 L vessel compared to the 16.80L vessel?
O The attractive forces between molecules become less ofa factor at the hisher pressure in the 3,80L vessel.
O The molecular volume is a smaller part of the total volume of the 3.8OL vessel.
O The molecular volume is a larger part of the total volume of the 3.80L vessel.
O The attractive forces between molecules become a greater factor at the higher pressure in the 3.80 L vessel.
II
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
General Chemistry - Standalone book (MindTap Cour…
Chemistry
ISBN:
9781305580343
Author:
Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:
Cengage Learning
Physical Chemistry
Chemistry
ISBN:
9781133958437
Author:
Ball, David W. (david Warren), BAER, Tomas
Publisher:
Wadsworth Cengage Learning,
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
General Chemistry - Standalone book (MindTap Cour…
Chemistry
ISBN:
9781305580343
Author:
Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:
Cengage Learning
Physical Chemistry
Chemistry
ISBN:
9781133958437
Author:
Ball, David W. (david Warren), BAER, Tomas
Publisher:
Wadsworth Cengage Learning,
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning