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Using data from the appendix, calculate AS each is spontaneous at 25°C. (a) 2 KCIO4(s)→2 KCIO3(s) + O₂(g) ,0 AS rxn rxn Is the reaction spontaneous at 25°C? O yes no AS = (b) 2 Na(s) + 2 H₂O() → 2 NaOH(aq) + H₂(g) surr = J/K yes no Aso J/K surr Is the reaction spontaneous at 25°C? (c) N₂(g) → 2 N(g) rxn and AS surr for each of the reactions and determine if x 10 J/K (enter your answer in scientific notation) J/K

Using data from the appendix, calculate AS each is spontaneous at 25°C. (a) 2 KCIO4(s)→2 KCIO3(s) + O₂(g) ,0 AS rxn rxn Is the reaction spontaneous at 25°C? O yes no AS = (b) 2 Na(s) + 2 H₂O() → 2 NaOH(aq) + H₂(g) surr = J/K yes no Aso J/K surr Is the reaction spontaneous at 25°C? (c) N₂(g) → 2 N(g) rxn and AS surr for each of the reactions and determine if x 10 J/K (enter your answer in scientific notation) J/K

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter10: Entropy And The Second Law Of Thermodynamics
Section: Chapter Questions
Problem 10.50PAE: For the reaction NO(g)+NO2(g)N2O3(g) , use tabulated thermodynamic data to calculate H and S. Then...
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0 Using data from the appendix, calculate AS each is spontaneous at 25°C. (a) 2 KCIO4(s)→→2 KCIO3(s) + O₂(g) Asº rxn O = Asº Is the reaction spontaneous at 25°C? yes rxn Aso no (b) 2 Na(s) + 2 H₂O() → 2 NaOH(aq) + H₂(g) surr J/K yes no Asº J/K surr Is the reaction spontaneous at 25°C? (c) N₂(g) → 2 N(g) rxn and AS surr for each of the reactions and determine if x 10 J/K (enter your answer in scientific notation) J/K < Prev 11 of 20 Next >
Transcribed Image Text:0 Using data from the appendix, calculate AS each is spontaneous at 25°C. (a) 2 KCIO4(s)→→2 KCIO3(s) + O₂(g) Asº rxn O = Asº Is the reaction spontaneous at 25°C? yes rxn Aso no (b) 2 Na(s) + 2 H₂O() → 2 NaOH(aq) + H₂(g) surr J/K yes no Asº J/K surr Is the reaction spontaneous at 25°C? (c) N₂(g) → 2 N(g) rxn and AS surr for each of the reactions and determine if x 10 J/K (enter your answer in scientific notation) J/K < Prev 11 of 20 Next >
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