Using the end-group analysis to find molecular weight, 6 mol of 1,4-butanediamine reacted with 6 mol 1,6-hexane-diacid (see formulas below). After the reaction titration was performed using Mg(OH)2 (which reacts with-COOH group only) to determine the number of acid groups remaining free after the polymerization. If 15 ml of 0.5M Mg(OH)z were required to neutralize the polymer, what is the average number average molecular weight (M,) of the polymer. 1,2-butanediamine: H2N - CH2 - CH2 – CH2 – CH2 – NH2 1,6-hexane-diacid: HOOC – CH2 – CH2 - CH2 – CH2 – COOH
Using the end-group analysis to find molecular weight, 6 mol of 1,4-butanediamine reacted with 6 mol 1,6-hexane-diacid (see formulas below). After the reaction titration was performed using Mg(OH)2 (which reacts with-COOH group only) to determine the number of acid groups remaining free after the polymerization. If 15 ml of 0.5M Mg(OH)z were required to neutralize the polymer, what is the average number average molecular weight (M,) of the polymer. 1,2-butanediamine: H2N - CH2 - CH2 – CH2 – CH2 – NH2 1,6-hexane-diacid: HOOC – CH2 – CH2 - CH2 – CH2 – COOH
Chapter31: Synthetic Polymers
Section31.SE: Something Extra
Problem 33AP
Related questions
Question
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 8 steps with 4 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you