Using the pedigree you have constructed, complete the following Punnett square using A/a. 1) Show the cross between Braxton and his non-albino wife who had an Mother's Alleles albino father: Mother's genotype: Father's genotype: Genotype %: Phenotype %: Father's Alleles
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- A. The man is heterozygous type B (BO) and the partner is homozygous type A (AA). Do the cross to show how it happens and answer the following: What are the different blood types and the corresponding genotypes of their kids? What is the chance or the probability to have a blood type B child? How about the chance to have a type AB child? If the couple plans to have 3 kids, how many combinations of blood types will be true for their kids? B. The two rabbits with these corresponding genotypes were mated; CCch X CCh. Do the cross and answer the following questions. How many phenotypes will there be for the offspring? How about the genotypes? What is the percentage of agouti offspring to come out? What is/are the other phenotype/s of the offspring besides agouti?Please answer all of them, they are all connected. PEDIGREE ANALYSIS and SYMBOLOGY: Examine the pedigree which has X linked Dominant inheritance of disorder. Use letter X* (asterisk denotes disorder) as genotype of the individuals which can be XX, XY, X*X*, X*X and X*Y. a. What is the genotype of IV-6? b. What is the genotype of III-6? c. What is the genotype of II-3? d. What is the genotype of III-8? e. If couple I-1 and I-2 will have a son, what is the probability of having the disorder? f. If couple III-8 and III-9 will have another child, what is the probability of having the disorder? g. Theoretically, if individual IV-3 and individual IV-5 will marry and will have a child, what is the probability of having a child without the X-linked disorder?If one parent is heterozygous for blood type B and the other parent is blood type AB , what are the possible blood types of the children? For reference, the alleles possible for blood typing are: IA |B i О А, В, АВ, О B or O A or B О А, В, АВ O A or O
- I * 1 1 I 2 1 13 1 14 1 16r 1 11171 Using the pedigree you have constructed, complete the following Punnett square using A/a. 1) Show the cross between Baila and her non-albino husband if he had no Mother's Alleles albinism in his family history: Mother's genotype: Father's genotype: Genotype %: Phenotype %: o add speaker notes Father's Alleles/d/1n5NtidRwTwUzcDkDPi5Z9P_SHPZ91A-XH-pfftLbhNc/edit (1) O pols Add-ons Help Last edit was seconds ago BIUA ミ: 12 + ext Calibri I|1 6 I 2 Section 5: Trihybrid cross and Laws of probability For a trihybrid cross, in which inheritance of alleles for three genes is tracked, drawing a Punnett square that combines all three genes may not be practical. Instead the laws of probability may be used. The product law of probabilities says that when alleles for separate genes segregate independently, we can figure out the probability of a particular combined genotype by multiplying the probability of the alleles for each gene. 13. We cross a homozygous tall pea plant with yellow, round seeds to a homozygous dwarf pea plant with green, wrinkled seeds. All the F1 offspring are all tall plants with yellow, round seeds. a. What are the expected F2 ratios (use fractions) of tall and dwarf plants? b. What are the expected F2 ratios (use fractions) of yellow and green seeds? C. What are the expected F2…Pretending that Park shin-hye is heterozygous for A blood type marries Choi Tae-joon whose blood type is O. Show the possible blood types of their future children. 1. P1: 2. Punnett Square: 3. Genotype symbols: 4. Genotype in words: 5. Genotypic ratio: 6. Genotypic %: 7. Phenotype symbols: 8. Phenotype in words: 9. Phenotypic ratio: 10. Phenotypic %:
- к, х Ааv AdBbCc AaBbCc No Spacing AaBbCc 三、相、 1 Normal Heading 1 Font Paragraph 6. Let's assume that the non-taster, daughter in question 5 is a carrier of the albino trait. She marries a Styles taster man, normally pigmented, whose mother was a non-taster albino. Show the cross between these parents. Genotype of the woman Genotype of the man Genotypes Phenotypes What is the chance that their child will be a taster? Footer What is the chance that their child will be albino? What is the chance that their child will be a taster albino? J.S.)Given the karyogram below, anSW Is this a male or female? female Do you see any abnormality? Yes 13 Write the karyotype (genetically speaking)|PEDIGREE: Shaded individuals in the pedigree have a genetic disease. Individuals marrying into the family, that is individuals II–1, II–4 and II–6, have no history of the disease in their families.1. Determine the mode of inheritance ______________________________2. Give the genotypes of the following individuals
- Parents Genotype : Bb/bb – Eye Color - (brown eyes dominant , blue eyes recessive) Dd- Dimples ( dominant) Cc/cc- Cleft chin (Dominant) Sarah BbDdcc James bbDdCc If they plan to have 4 children, what is the probability of having: a) all girls with blue eyes and dimples b) 2 children with dimplesA man with Type AB blood is married to a woman with Type O blood. They have 2 natural children and one adopted child. Their blood types are shown below: Jane-A Bobby - B Gracie O Which child is adopted? Complete the Punnett Square below and answer the questions that follow. List the possible genotypes: List the possible phenotypes Who is the adopted child? Explain your answer using the information from the Punnett square.For Questions 1-7; answer with the phenotypic and genotypic ratios for each cross. Question 8; review co-dominance in your book and lecture notes. Genetics-Heredity Study Guide Name %23 Date Section Concepts/Words to know: Gregor Mendel P, F1, F2 Generations Homozygous Pea Plants Dominant and recessive Genetic disorders Autosomal X-linked recessive Codominant X-linked Carrier Incomplete Dominance Heterozygous Allele Blood Types and transfusions Pedigrees Punnett Square Hemophilia ereen peaplant (GRlis crossed w uayellow pea plant BB)- A tal plant (T1) scrossed A tall plant (Tt) is crossed with a shortp A red flower (Rr) is crossed with a white flower (m). 5) A white flower (r) is crossed with a white flower (r). attan is 7. Two heterozygous white (brown fur is recessive) rabbits are crossed. 8. In some chickens, the gene for feather color is controlled by codiminance. The heterozygous phenotype is known as erminette. a. What is the genotype for black chickens? b. What is the genotype…