Using the substitutions Z = sin y and dz=cos y dy, the differential equation (3sin y – 5x)dx + 2x² cot y dy=0 reduces to A z(3z-5x) dx - 2x² dz = 0 B (3z-5x) dx - 2x² dz =0 (3z - 5x) dx + 2x² dz =0 z(3z -5x) dx + 2x² dz = 0 %3D

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