linear alg, Vector SpacesProve property 3 by rearrangingthe fligProperty 3: For every element A, B, C in V=M3x3,(AB) C= A + (BDC)A) Letaij, bij, cij, dij, ei; and the with entries inA₁B₁C₁D = (ABB) + C, E = A (BOC), respectivelyB) Suppose A, B, and C are in V = M3x3в)c) from the definition of AB, dij -(aijx bij) x cij and eij =a i j x (bij x c i j )420932D) SO, (AⓇB) ⓇC = A + (PDC)ESince aij, bij, cij are real #'s dij=eijansueanswer for ex FEDCBAAXAwh tast

Answered: Image /qna-images/answer/1e77b161-d639-448b-84d5-2218795e8bd6.jpg

Vector Spaces Prove property 3 by rearranging the flig Property 3: For every element A, B, C_₂in V=M3x3, (ABB) CAD (BDC) A) Let aij, bij, cij, dij, ei; and the aith entries in A₁B₁C₁D = (ABB) # C, E = A (B+C), respectively 2 Suppose A, B, and C are in V = M₂x3 • from the definition of AB, dij -fai jx bij) x cij and eij aijx (bij x cij) So, (AB) C = A + (PDC) Since aij bij cij are are real #'s dijseij answer for ex FEDCBA M

Vector Spaces Prove property 3 by rearranging the flig Property 3: For every element A, B, C_₂in V=M3x3, (ABB) CAD (BDC) A) Let aij, bij, cij, dij, ei; and the aith entries in A₁B₁C₁D = (ABB) # C, E = A (B+C), respectively 2 Suppose A, B, and C are in V = M₂x3 • from the definition of AB, dij -fai jx bij) x cij and eij aijx (bij x cij) So, (AB) C = A + (PDC) Since aij bij cij are are real #'s dijseij answer for ex FEDCBA M

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter2: Systems Of Linear Equations

Section2.3: Spanning Sets And Linear Independence

Problem 21EQ

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