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- int main() { E(); C(); E(); } void B() {...} void C() {..} void D() {..} void E() { B(); D(); } A variable declared in function B and only in function B is accessible in?class Test { char paper[20]; int marks; public: Test () // Function 1 { strcpy (paper, "Computer"); marks = 0; } Test (char p[]) // Function 2 { strcpy(paper, p); marks = 0; } Test (int m) // Function 3 { strcpy(paper,"Computer"); marks = m; } Test (char p[], int m) // Function 4 { strcpy (paper, p); marks = m; } }; i. Write statements in C++ that would execute Function 1, Function 2, Function 3 and Function 4 of class Test. ii. Which feature of Object Oriented Programming is demonstrated using Function 1, Function 2, Function 3 and Function 4 together in the above class Test?Outputs of the following: void main () { int M[3]; int *ptr; ptr=M; *ptr=D100; ptr++; *ptr=200; ptr=&M[2]; *ptr=300; for (int n=O; n<3; n++) cout <12.14 Zylab 3 - Single Procedure Call Given an array of at least one integer, write a program to create a new array with elements equal to the power of each element in the original array raised to the index, i.e., P[i] = A[i]^i. For this, write two functions that will be called in main function independently. ● power inputs: element (A[i]) and index (1) • task: returns the value of element raised to index (A[i]^i). } O • newElement inputs: base address of new array P (*P), current size of P (variable k) and the new element (A[i]^i) o task: add the new element at the end. o This function does not return any value (void). O Following is a sample C code to perform the required task. You may modify the code for the functions, but the task performed should not be changed. int main() { // Variable Declaration int *A, *P; int n, k; int pow; // Task of main function P[0] 1; for (int j = k = j; pow // Base addresses of A and P // Lengths of arrays A and B // Return value from power function }…Consider the following function: void fun_with_recursion(int x) { printf("%i\n", x); fun_with_recursion(x + 1); } What will happen when this function is called by passing it the value 0?PROGRAMMING LANGUAGE: C++ // vectors: overloading operators example#include <iostream>using namespace std;class counter{private:int count;public:counter():count(0){}counter(int c):count(c) {} int get_count(){return count;} counter operator++ (int){return counter(count++); } counter operator-- (int){return counter(count--);}};int main(){counter c1, c2, c3;c1++;c2--;cout<<'\n'<<c1.get_count();cout<<'\n'<<c2.get_count();cout<<endl;c3 = c1++;cout<<'\n'<<c1.get_count();cout<<'\n'<<c3.get_count();getch();return 0;} Go through the above code and write the output of the given code segment. counter c1(5), c2(10), c3;c3=c1++;c2=--c3;;cout<<”\n”<<c1.get_count();cout<<”\n”<<c2.get_count();cout<<”\n”<<c3.get_count();Your task is to create two classes namely data and calculation. The calculation class is a friend of the data class. The data class will be composed of two floating point data members namely a and b. The class will also be composed of a friend function display that can display all the data members.A/ find code optimization method to this code and then find type to this code 1- For(i=1;imain.cpp:4:17: error: 'string' has not been declared 4 | void KMPSearch(string pat, string txt) main.cpp:4:29: error: string' has not been declared 4 | void KMPSearch(string pat, string txt) Aununun main.cpp:31:25: error: string' has not been declared 31 | void computelPSArray(string pat, int M, int[] lps) main.cpp:31:50: error: expected or . before lps' 31 | void computeLlPSArray(string pat, int M, int[] lps) main.cpp:55:8: error: expected :' before 'static' 55 | public static void Main() main.cpp:61:2: error: expected ;' after class definition 61 | } | main.cpp: In member function 'void GFG::KMPSearch(int, int)': main.cpp:6:15: error: request for member Length' in 'pat', which is of non-class type 'int' 6 | int M = pat.Length; main.cpp:7:15: error: request for member Length' in txt’, which is of non-class type 'int' int N = txt.Length; main.cpp:8:6: warning: structured bindings only available with -std3c++17' or (-std=gnu++17' 8 | int[] lps new int[M];function myCompose(f,g){// TODO: return (f o g);// that is, a function that returns f(g(x)) when invoked on x.}A return; else #include using namespace std; void division (int num, int denom); int main() { division (5, -1); division (10, 2); return 0; } void division (int num, int denom) {if (denom using namespace std; int main() (char List[4][10] = {"kareem", "ahmed", "ali", "mohamed"}; cout<SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. 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