What are the maximum and minimum number of rows returned by the RI right outer join R2? a. Min-rows in R2, max-rows in R1 rows in R2 . Min-0, max-rows in R1+ rows in R2 Cc. c. Min-0, max-(rows in R1 + rows in R2)- 1 d. . Min-rows in R2, max- (rows in RI + rows in R2)-1
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- What are the maximum and minimum number of rows returned by the R1 right outer join R2?a. Min = rows in R2, max = rows in RI * rows in R2b. Min = 0, max = rows in R1 + rows in R2c. Min = 0, max = (rows in R1 + rows in R2) - 1d. Min = rows in R2, max = (rows in RI + rows in R2) - ISQL: Create a SQL query that uses an uncorrelated subquery and no joins to display the descriptions for products provided by a vendor in area code 615. Remember, the main difference between a correlated subquery and uncorrelated subquery is that, in a correlated subquery, the inner query is dependent upon the outer query, while, with an uncorrelated query, the inner query does not depend upon the outer query. Instead, it runs just once. You should NOT use union, minus, or intersect in this query. The outer query will use the PRODUCT table and the inner query will use the VENDOR table [hint: you should have 9 records of output]. My code: select p_descript from product where (select v_areacode from vendor where v_areacode = '615' ; I am getting this error, problem is I can't see what is missing any assistance is appreciated. ORA-00936: missing expressionWhat are the maximum and minimum number of rows returned by the R1 right outer join R2? a. Min = rows in R2, max = rows in R1 * rows in R2 b. Min = 0, max = rows in R1 + rows in R2 c. Min = 0, max (rows in R1 + rows in R2) - 1 d. Min rows in R2, max = (rows in R1 + rows in R2) – 1 6.
- Fix all individual code.In java create an application to manage your data base information the database is already created in mysql tables, the tables are fill, So the user can use your database application user friendly Retrieve all data: Given a table name, retrieve all data from the table and present it to the user. Average: Given a table name and a column name, return the average of the column. Here the assumption is that the column type will be numeric (e.g., cost column). Insert: Given a table name, your program should show the column names of that table and ask the users to input new data to the table. In case of errors, your program should directly show the MySQL errors to the users. Assumption 1: Users will enter data according to the database constraints. Assumption 2: Users will input one record at a time. Delete: Given a table name, your program should show the column names of that table and ask the users to input data that they want to delete. Assumption 1: Users will enter data according to the…Identify the difference between blocking and non-blocking assignments. Explain the situation when you would be using them in your Verilog code.
- Which of the following function chooses a random index as the pivot? A. int Median(arr, left, right) { int mid; mid = (left + right)/2 if (arr[right] < arr[left]); Swap(arr, left, right); //to swap arr[left],arr[right] if (arr[mid] < arr[left]); Swap(arr, mid, left);//to swap arr[left],arr[mid] if (arr[right] < arr[mid]); Swap(arr, right, mid);// to swap arr[right],arr[mid] return mid; } B. int Median(arr, left, right) { int mid; mid = (left + right)/2 if (arr[right] > arr[left]); Swap(arr, left, right); //to swap arr[left],arr[right] if (arr[mid] < arr[left]); Swap(arr, mid, left);//to swap arr[left],arr[mid] if (arr[right] < arr[mid]); Swap(arr, right, mid);// to swap arr[right],arr[mid] return mid; } C. int Median(arr, left, right) { int mid; mid = (left + right)/2 if (arr[left] < arr[right]); Swap(arr, left, right); //to swap…The following code will #define N_ROW 10 #define N_COL 10 int row; double sum=0, table[N_ROW][N_COL]; sum = 0; for (row = 0; row < N_ROW; row++) sum += table[row][1] sum the values of the column with an index of 1. sum the values of the row with an index of 1. sum the values of the row with an index of N_ROW. none of the others sum the values of the first column in the array.Question 15 kk .ent is not defined, click the undefined button. D=[[-1,12,-3,-6,10],[-10,4,-9,3,-2],[-7,8,9,-8,-5],[7,-4,-11,2,0],[11,5,1,6,-12]] Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line
- Can you please exlain step by step .Thank youdef read_routes (routes_source: TextI0, airports: Airport Dict) -> RouteDict: "Return the flight routes from routes_source, including only the ones that have an entry in airports. If there are multiple routes between routes_source and a destination (on different airlines for example), include the destination only once. Routes that include null airport IDs should still be included, but routes that have empty IATA should be excluded. TENN >>> from io import StringI0 >>> routes src= StringIO(TEST_ROUTES_SRC) >>> actual = read_routes(routes_src, TEST AIRPORTS_DICT) >>> actual == TEST_ROUTES_DICT_FOUR_CITIES True DE TELE {} routes = src_index ROUTE_DATA_INDEXES["Source airport"] dst index ROUTE_DATA_INDEXES["Destination airport"] # Complete this function. # Note that each value in the resulting Hictionary is a set of IATA codes.Which of the following function chooses a random index as the pivot? A. int Median(arr, left, right) { int mid; mid = (left + right)/2 if (arr[right] arr[left]); Swap(arr, left, right); //to swap arr[left],arr[right] if (arr[mid] < arr[left); Swap(arr, mid, left);//to swap arr[left],arr[mid] if (arr[right] < arr[mid]); Swap(arr, right, mid);// to swap arrſright],arr[mid] return mid; } С. int Median(arr, left, right) { int mid; mid = (left + right)/2 if (arr[left] < arr[right]); Swap(arr, left, right); //to swap arr[left],arr[right] if (arr[left] < arr[mid]); Swap(arr, mid, left);//to swap arr[left],arr[mid] if (arr[right] < arr[mid]); Swap(arr, right, mid);// to swap arr[right),arr[mid] return mid; } D. int Median(arr, left, right) { int mid; mid = (left + right)/2 if (arr[right] < arr[left); Swap(arr, left, right); //to swap arr[left],arr[right] if (arr[left] < arr[mid]); Swap(arr, mid, left);//to swap arr[left],arr[mid] if (arr[mid] < Swap(arr, right, mid);// to swap…
