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- Please answer it in Python Write a function min_odd that takes a list as an argument and returns the smallest even integer contained in the list. If the list contains no even integers, the function will return None. For Example : min_odd([45, 62, 19, 22, 26, 18, 3, 5, 14])Expected answer is 14 min_odd([])Expected answer is None Write a function index_of that takes as an argument an integer (supposedly even) and a list, and returns the index to which this integer appears in the list. If the integer does not appear, the function will return None. It is assumed here for simplicity that the integer searched for does not appear several times in the list. Hint: if the for e in list loop doesn't suit you, remember that you can make a for + range or a while. .. For Example: index_of(34, [3, 67, 62, 34, 19, 24])Expected answer is 3 index_of(16, [2, 6, 104, 5, 25, 18, 50, 16])Expected answer is 7PLZ write in SML language. Thank you Write a function maxGroup that determines, for a given integer list, the stored number of the longest consecutive group of equal numbers. For example, maxGroup [2, 9, 8, 8, 8, 7, 9, 1] should return 8 since there are three consecutive 8s in the list. Hint: Solve the problem in two steps. First, determine the length of each group of equal numbers. Then, determine which is the largest.Define the function (siftNum lst). This function should resolve to all the numbers in the list, lst. For example: (siftNum '(a 8 2 1 m l 90 p 2)) resolves to '(8 2 1 1 90 2).
- Write a function littler_indices (integers, upper_limit) that returns a list of the indexes of every element in the given list integers that is less than upper_limit. Check the test cases for how the function should work. For example: Test Result nums = [10, 20] i_list = littler_indices (nums, 15) [0] print(i_list) numbers = [10, 20, 25, 5, 30] (0, 3] indices = littler_indices (numbers, 20) print(indices) empty = [] indexes = littler_indices (empty, 42) [] print(indexes)Write a function summax2 : int list -> int = that takes an int list and returns the sum of the 2 largest integers in it. 1 # summax2 [1;4;6;2;7;8; 3 ; 10 ; 4; - 1] ; ; 2 - : int = 18 3 # summax2 [1;4];; 4 - : int = 5 5 # summax2 [1]; ; 6 - : int - 1 7 # summax2 []; ; int = 05. The following function indexCounter aims to find and return all the indices of the element x in a list L. if x is not in the list L, return an empty list. However, the implementation has a flaw, so that many times it will return error message. Can you fix the flaw? def indexCounter(L, x): indexList [] startIndex = 0 while startIndex < len(L): indexList.append (L.index (x, startIndex)) startIndex = L.index (x, startIndex) + 1 return indexList
- 2. listAverage() returns the average number in a list. Which of these functions does this correctly? O A. function listAverage (1ist) ( var sum - for ( var 8 0: 0< list length sum- sum + 1ist A return sum / ist.length O B. tunction listAverage (list){ var sum for( var 8 0: Ise. 1ength sum sum + Ist O return sum / 1ist length . function listAverage (list) ( var sum= return sum / HElength) for ( var 0 0Write a function print_matching_indexes (items, target) that prints the indexes of all the occurrences of the target in the list items. Check the test cases for how the function should work. Note: Your answer must use a for loop. You are not allowed to use a while loop. For example: Test Result nums = [10, 20, 30] 1 print_matching_indexes (nums, 20) pets = ['dog', 'cat', 'fish', 'cat', 'dog', 'iguana'] 1 print_matching_indexes (pets, 'cat') 3 empty = [] print_matching_indexes (empty, 42)Write a function get_list_avg() that expects a parameter main_list (a list of lists) and returns a new list that contains the average of each sub-list in main_list. The function should return an empty list if the main_list is empty. this is my answer: def get_list_avg(main_list ): new_list = [] for sublist in main_list: avg = sum(sublist) / len(sublist) new_list.append(avg) return new_list main_list = input() print(get_list_avg(main_list))Please answer it in Python Write a function insere_milieu that takes as an argument a list l and an element elem and returns the list obtained from l by adding elem "in the middle" of l, that is: If the length of l is even, the item is added once, in the middle of the list. If the length of l is odd: the element is added on either side of the central element. Example: insere_milieu([4, 7, 12, 3], 0) is [4, 7, 0, 12,3] insere_milieu([9, 3, 5, 6, 2], 1) is [9, 3, 1, 5, 1, 6, 2].CLO3: Analyze the given function below that takes a binary list of size (n) and returns the number of 1's, O's and sum of 1's in the list. Answer the questions below: def function(List): zeroCount = 0 oneCount = 0 onesSum=0 for i in range(len(List)): if Listfi) - 0: zeroCount +=1 else: oneCount += 1 onesSum += 1 print ('Number of Zeros =', zeroCount) print ('Number of Ones =, oneCount) print ('Sum of Ones =', onesSum) 1. Count the number of steps required by the function in terms of n? (" 2. What is the time complexity of the algorithm. (1. 3. Find number of operations if (n = 20).Write a function getOdds() that takes a list of integer numbers as parameter, returns a new list made of only the odd numbers in the list.Example: If the parameter list contains [44, 81, 7, 24], the function will return [81, 7].SEE MORE QUESTIONS