What is the equation for y? Inputs: b Outputs: y, z yz = 00 yz = 11 *State encodings are in red Oy=z Oy=pb' Oy=p O y = n' Combinational Logic 네 State register POO DO b CO 0 0 0 0 0 1 1 0 1 1 0 0 1 0 N 0 0
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- Q: for the 4-bit binary adder - subtractor , the control signal M control the operation 4 - bit Binary Adder-Subtractor В, А, 1 0 В, А, A3 B3 1 0 B, A, 1 0 1 0 1 0 M B3B3 Bz'\B2 C3 BoBo C; C2 Co FA FA FA FA C4 S3 S2 So M=0,C0=1 & B(XOR)0=B with M=1,C0=0 & B(XOR)0=B' M=0,C0=1 & B(XOR)0=B' with M=1,C0=0 & B(XOR)0=B M=0,C0=1 & B(XOR)0=B' with M=1,C0=1 & B'(XOR)0=B M=0,C0=0 & B(XOR)0=B with M=1,C0=1 & B(XOR)1=B'Manchester encoding guarantees frequent clock synchronization by changing signal values. What is the maximum number of bits which may be encoded without a signal change? (Note: The way this question has been asked. you are not to include the bit which includes a signal change in your count)The data word 10101110001101 is given for transmission. Draw the following encoding formats. NRZ-L NRZ-I Bi-phase Manchester RZ Differential Manchester
- write verilog code for following 2 to 4 decoder yo メ メ 2 toy ら- decoderExo 3 1+ The number whose code us 11.00 110 s in 2's complement on 8 bits is: A. 35 B₂ - 41 C. -51 61 2+ BCD character ending allows to code on! At 10 bots B = I bits. G+ 6 bits. Dt 8 bits 3- What is the encoding of A - 10100010 B- 110 111 11 ct 10110101 D- 1 1 0 1 1 1 1 0 (-34) 10 in 2's complement?An 8-bit byte with binary value 10101111 is to be encoded using an even-parity Hamming code. What is the binary value after encoding? ANS: The encoded value is 101001001111 Why is this answer longer from binary value? Please solve this question with details. Please explain why you use that method.
- b) Using ASCII encoding (table), what is the binary representation of the letters below (case sensitive). 0 1 2 3 4 5 6 7 SigMa 0 2 5 6 1 3 4 NUL SOH STX ETX EOT ENQ ACK DLE DC1 DC2 DC3 DC4 " SP ! 0 1 @ A P Q a q Р 2 B R b musun $ 4 D T d 7 8 BEL BS HT NAK SYN ETB CAN % & ( ) 8 9 : H I J X Y Z h i j X y Z t SE3 5 U e u 6 F V f V . TCM6.0 3 7 G W W 9 A EM SUB * BCDE LF VT FF CES ESC FS + ; K k -VL7~- CR SO GS RS M 1 ] m 13 > ZV. 455120 10W F SI US ? DELFor the FSM below, assume to start from state S0 and to use the indicated encoding. The following sequence of inputs are going to be selected one after the other at times t0, t1, t2, t3, and t4. Use the FSM to indicate the next state bits and output Y after each time point. t0 -> AB=00 t1 -> AB=10 t2 -> AB=11 t3 -> AB=11 t4 -> AB=01 Indicate your answer using 3 bits for each time point. For example, if AB=10 at time t0, your answer would be 101, where the first two bits are for the next state (10 -> S2) and the third bit is for the output value YIf the floating-point number representation on a certain system has a sign bit, a 3-bitexponent and a 4-bit significand: • What is the largest positive and the smallest positive number that can be stored on this?system if the storage is normalized? (Assume no bits are implied, there is no biasing,exponents use two's complement notation, and exponents of all zeros and all ones areallowed.)• What bias should be used in the exponent if we prefer all exponents to be non-negative?Why would you choose this bias? show work and write out solution
- Huffman encoding uses longer codes for more frequently occuring symbols. True FalseTable entries (C) and (D) correspond to what values? Inputs: g Outputs: y, z 00 yz = 01 9 9 01 9' *State encodings are in red C = 0, D = 0 C = 0, D = 1 O C= 1, D = 0 O C=1, D = 1 00 U 10 y2 = 10 Combinational Logic p1 po State register n1 noT S t u unused p1 po g 0 0 0 0 0 1 0 0 1 1 1 1 10 1 0 0 1 0 1 1 0 1 1 n1 no y Z 0 0 (C) (D)Consider an S-box that takes 8 bits as input and generates a 2-bit output. The first and second bits of the input are XOR-ed to give the first bit of the output. The seventh and eighth bits of the input are XOR-ed to give the last bit of the output. What is the output if the input is 01110101?