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What is the mass of 9.45 moles of Al2O3? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole Al, 0, 9.45 moles Al2O3* 102.2 grams of Al, O₂ Is this answer correct? = 0.0926 grams of Al₂O3

What is the mass of 9.45 moles of Al2O3? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole Al, 0, 9.45 moles Al2O3* 102.2 grams of Al, O₂ Is this answer correct? = 0.0926 grams of Al₂O3

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.16PAE: 4.16 Many metals react with halogens to give metal halides. For example, iron reacts with chlorine...
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Include a CLAIM: answer the question. Is this correct or not?

Include EVIDENCE: Describe what you see in the calculation work that supports your claim.

Include REASONING: Explain WHY you selected that evidence to support your claim.

 

Hint attached.

A 1 mole = 6.02 x 10²³ particles ✓ N 6.02 x 10 particles 1 mole C 6.02 x 10¹ particles B 1 mole = molar mass* (grams) "S determined by summing the ma 1 of all elements in the formula 1 mole = 22.4 L of gas Inde 7241 22.4 L
Transcribed Image Text:A 1 mole = 6.02 x 10²³ particles ✓ N 6.02 x 10 particles 1 mole C 6.02 x 10¹ particles B 1 mole = molar mass* (grams) "S determined by summing the ma 1 of all elements in the formula 1 mole = 22.4 L of gas Inde 7241 22.4 L
In class, students were given the following problem: "Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a coating of aluminum oxide (Al2O3) according to the following chemical equation: 4Al(s) + 302(g) →2A/203(s) What is the mass of 9.45 moles of Al 203? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole AL, Q 9.45 moles Al₂O3× 102.2 grams of Al, 0, Is this answer correct? = 0.0926 grams of Al2O3
Transcribed Image Text:In class, students were given the following problem: "Aluminum satellite dishes resist corrosion because aluminum reacts with oxygen gas (0₂) to form a coating of aluminum oxide (Al2O3) according to the following chemical equation: 4Al(s) + 302(g) →2A/203(s) What is the mass of 9.45 moles of Al 203? After correctly solving for the molar mass of Al2O3, Jacob set up the following conversion: 1 mole AL, Q 9.45 moles Al₂O3× 102.2 grams of Al, 0, Is this answer correct? = 0.0926 grams of Al2O3
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