What is the output of the following code: SHR SI, 1 (SI=93ADH CF=0) O Skip SI-49D6H CF=1 OSI= 34ADH CF=0 OSI=45D5H CF=0 O SI=D93AH CF=1
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- After execution of the following code: MOVLW 9Fh ADDLW 61h Select one: a. C=0 DC=0 Z=1 b. C=1 DC=1 Z=1 c. C=0 DC=1 Z=0 d. C=0 DC=1 Z=1b = mod(24,5) b = 3 b =6 b =5 b =4By using loop principle design the below from and write tbe code ****Q5**** BBBBBBBBBA BBBBBBBBAB BBBBBBBABB BBBBBBABBB BBBBBABBBB BBBBABBBBB BBBABBBBBB BBABBBBBBB BABBBBBBBB ABBBBBBBBB ****END****
- ax2 + bx + c = z (in programming format)Point out the difference between int pthread_mutex_lock ( pthread_mutex_t *mutex_lock); and int pthread_mutex_trylock ( pthread_mutex_t *mutex_lock);Create a VBA algorithm that calculates the weighted grade of four exams of 10 students. Column 1 – Student’s Name Column 2 –Exam 1 Score Column 3 – Exam 2 Score Column 4 – Exam 3 Score Column 5 – Exam 4 Score Column 6 – Weighted Grade Formula of Weighted Grade: Weighted Grade = 30% Exam 1 + 25% Exam 2 + 25% Exam 3 + 20% Exam 4
- Write a mipscode for the function that evaluates and prints the sum of the numbers between two number For example : if the two number were 2 and 5 the result would be 14When you write a hex data consisting of first digit from A to F, you should suffice a ---------- .Simplify the following expression: Ei=o 2* (4). k=0
- Convert the following infix expression to postfix and prefix expression.K+L-M*N+(O^P)*W/U/V*T+QQ : Write algorithm and Pseduocode for Grade and CGPA calculation.In execution of the following code with the following bytes contents: START: CLC MOV CX, 0002 MOV SI, 0300 MOV DI, 0302 LOOP: MOV AL, (DI) ADC (SI), AL INC SI INC DI DEC CX JNZ LOOP HLT (0300H) = 1AH, (0301H) = 2BH, (0302H) = 3CH, (0303H) = 4DH. %3D %3D %3D The result will be: