What is the phenotype of an individual with the genotype XXXY? female, with an inactivated Y chromosome male, with one Barr body female, with one Barr body O male, with two Barr bodies female, with an inactivated Y chromosome
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- Under what condition might a human male have the XX sex chromosome complement? It is not possible. She has an X chromosome lacks an active Xist gene. He has an X chromosome that carries an SRY gene. He has a mutation that renders the SOX9 gene non-functional. He has a mutation that renders the SRY gene non-functional.is AC genotype normal?Hemophilia A is transmitted by an X-linked recessive gene.With an affected father, what is the probability that a childwill have the disease? With an affected father and a carriermother, what is the probability?
- Draw and label the mitotic phases (prophase, metaphase, anaphase & telophase) and meiotic phases (prophase I, metaphase I, anaphase I, telophase I, prophase II, metaphase II, anaphase II, & telophase II) for 2N=6. Be sure to indicate the chromosomal complement at each stage and whether the chromosomes are duplicated (consisting of sister chromatids) or not. For the meiotic phases, please add the following labels to your diagrams: In prophase I: tetradIn metaphase I: nonsister chromatidsIn anaphase I: homologous chromosomes, kinetochore microtubule In telophase I: sister chromatidsIn prophase II: centriolesIn metaphase II: centromereIn anaphase II: nonkinetochore microtubule, astral raysIn telophase II: cleavage furrowThe genotype XXY corresponds to Klinefelter syndrome Turner syndrome Triplo-X Jacob syndrome10- A man with X-linked color blindness marries a woman with no history of color blindness in her family. The daughter of this couple marries a normal man, and their daughter also marries a normal man. What is the chance that this last couple will have a child with color blindness? Assume the chance to have a daughter or a son is equal. a) 3/8 b) 1/8 C) 1/16 d) 3/4 02040 e) 1/4 Boş bırak