What is the probability of having two daughters and 1 son? Child #1 == of being XX Child #2 = -1/2 of being XX child #3 = -1/2 of being XY 144/1/2 Correct answer= My answe 3
What is the probability of having two daughters and 1 son? Child #1 == of being XX Child #2 = -1/2 of being XX child #3 = -1/2 of being XY 144/1/2 Correct answer= My answe 3
Chapter5: What Is In A Name
Section: Chapter Questions
Problem 3S
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Why is this answer 3/8. Why do you add 1/8 three times? How would this question be worded for the answer to be 1/8?
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