What is the total entropy change at 25oC for the reaction below, if the standard entropies of reactants and products are So (C(gr)) = 5.74 J/mol*K, So (H2(g)) = 130.68 J/mol*K, and So (C6H10(g)) = 369.5000 J/mol*K and the heat of formation of C6H10(g)) is 123.7000 kJ/mol. (PLEASE SOLVE WITH CLEAR HANDWRITING) 6C(gr) + 5H2(g) ↔ C6H10(g) ΔSototal = 733.441 J ΔSototal = -318.340 J ΔSototal = -733.441 J ΔSototal = 318.340 J
What is the total entropy change at 25oC for the reaction below, if the standard entropies of reactants and products are So (C(gr)) = 5.74 J/mol*K, So (H2(g)) = 130.68 J/mol*K, and So (C6H10(g)) = 369.5000 J/mol*K and the heat of formation of C6H10(g)) is 123.7000 kJ/mol. (PLEASE SOLVE WITH CLEAR HANDWRITING) 6C(gr) + 5H2(g) ↔ C6H10(g) ΔSototal = 733.441 J ΔSototal = -318.340 J ΔSototal = -733.441 J ΔSototal = 318.340 J
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter16: Thermodynamics: Directionality Of Chemical Reactions
Section: Chapter Questions
Problem 113QRT
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What is the total entropy change at 25oC for the reaction below, if the standard entropies of reactants and products are So (C(gr)) = 5.74 J/mol*K, So (H2(g)) = 130.68 J/mol*K, and So (C6H10(g)) = 369.5000 J/mol*K and the heat of formation of C6H10(g)) is 123.7000 kJ/mol. (PLEASE SOLVE WITH CLEAR HANDWRITING)
6C(gr) + 5H2(g) ↔ C6H10(g)
6C(gr) + 5H2(g) ↔ C6H10(g)
ΔSototal = 733.441 J
ΔSototal = -318.340 J
ΔSototal = -733.441 J
ΔSototal = 318.340 J
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