What type of process (CPU-bound or I/O-bound) does the regressive round-robin scheduler favor?
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A variation of the round-robin scheduler is the regressive round-robin scheduler. This scheduler assigns each process a time quantum and a priority. The initial value of a time quantum is 50 milliseconds. However, every time a process has been allocated the CPU and uses its entire time quantum (does not block for I/O), 10 milliseconds is added to its time quantum, and its priority level is boosted. (The time quantum for a process can be increased to a maximum of 100 milliseconds.) When a process blocks before using its entire time quantum, its time quantum is reduced by 5 milliseconds, but its priority remains the same. What type of process (CPU-bound or I/O-bound) does the regressive round-robin scheduler favor? Explain.
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- NOTE: "Exekveringstid(ms)" means execution time or burst time in milliseconds Assume that a system with a CPU at one time has the following processes queued in the CPU's READY queue: Calculate the waiting time for the seven processes: 1) If FCFS is being used 2) If LRU is being used 3) If RR with time quantum of 8msA variation of the round-robin scheduler is the regressive round-robin scheduler. This scheduler assigns each process a time quantum and a priority. The initial value of a time quantum is 50 milliseconds.However, every time a process has been allocated the CPU and uses its entire time quantum (does not block for I/O), 10 milliseconds is added to its time quantum, and its priority level is boosted. (The time quantum for a process can be increased to a maximum of 100 milliseconds.) When a process blocks before using its entire time quantum, its time quantum is reduced by 5 milliseconds, but its priority remains the same. What type of process (CPU-bound or I/O-bound) does the regressive round-robin scheduler favor?When allocating process execution to the I/O queue, what are the advantages of doing so first? If the I/O is interrupted, what do you believe will happen? Will this have an impact on the CPU's burst rate? What do you mean by that?
- Determine what is the type of decision mode (non-preemptive or preemptive) to be exercised on a process during uniprocessor scheduling under the following circumstances: a. A process is aborted. Interrupt take place based on a certain clock interval. A process is requesting for I/O. A new process arrival. A process is requesting for operating system services.You are told that a given system uses Segmentation. The memory is currently full and holds 3 processes "A", "B" and "C" each of size 512KB as well as the kernel whose size is 1024KB. You can assume there is nothing else that is taking up memory. A Timer Interrupt forces a context switch to occur and the scheduler chooses to load process "B" into the CPU and change its state to running. You are told that the base of the stack which grows upwards for processB is found at the very end of our physical memory. You are also told that the last portion of the Address Space for each process is used for the Stack. After the Context switch which process does the values in the segment register correspond to? C + x What is the Physical Address of the base of the stack for ProcessB? (Just give the value in KB) 1536 What is the offset of the Virtual Address 500KB in KB? (Just give the value) 32 What is the Physical Address that the Virtual Address 500KB maps to in KB? (Just give the value) 1524Computer Science Suppose for a processor system it takes 35 cycles to push and pop registers onto the stack and change the PC value to the start of the interrupt service routine (ISR) or return from it. Suppose also that the ISR software takes additional 45 cycles to store the process state before the actual ISR body begins its work, and suppose it takes the same number of cycles to restore the process state when ISR is finished. If the ISR body takes 1000 cycles, what is the percent total overhead every time the ISR is executed? If the processor is running at a 2 GHz clock frequency, how long does it take before the ISR body begins execution in nanoseconds? This is usually called the ISR latency
- In disabling interrupt synchronization method, a process must disable interrupt just afterentering a critical section and re-enable it just before leaving it. In a multiprocessorsystem, a particular process P1 disables interrupt after entering a critical section byusing one CPU and meanwhile another CPU has interrupt enable flag set to 0. Anotherprocess P2 wants to enter the critical section by using any of the two CPUs. Suggestwhat could occur in this scenario.In a multiprogrammed environment with 32MB of RAM where all processes require9MB of unshared RAM and spend 40% of their time in I/O wait, calculate themaximum achievable CPU utilization. If the RAM available is increased by 700%and time spent in I/O wait increases by 100%, calculate how much RAM will remainunused when CPU utilization is just above 99%.Round Robin CPU Scheduling can be implemented to include priorty for the processes. Yanıtınız: True False Yanıtı temizle Gönder
- In the context of an operating system, an interrupt is a mechanism that allows the CPU to temporarily halt its current execution and switch to a different task or process in response to an external event. Interrupts are crucial for efficiently managing input/output (I/O) operations. Explain interrupts in I/O operations and provide an example to illustrate the concepts.When it comes to process execution, what is the advantage of first allocating it to the I/O queue and then pushing it to the CPU when it is ready? What, in your opinion, will happen if the I/O is not completed correctly? Is the CPU burst going to be affected? What do you mean?A process's execution may be preemptively assigned to an I/O queue and then transferred to the CPU when it's ready. There's no telling what may happen if the I/O is suddenly cut off. Is the CPU's burst going to be diminished? How exactly does this hold true?
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