What would be missing line of code Use currRecording's ReadDiscount And Topic() to read each pair of inputs, character discount and string topic, until 'Z' is read frominput and currRecording's Read DiscountAnd Topic)) returns false. If currRecording's Read DiscountAnd Topic() returns true, appendcurrRecording to vector recording List.Ex: If the input is Y Housing Y Environment Y Jewelry Z, then the output is:Recording discount: Y, Topic: HousingRecording discount: Y, Topic: EnvironmentRecording discount: Y, Topic: Jewelry2930 }3132 int main() {33343536373839404243444546}cout << "Recording discount: "<< discount << ", Topic: " << topic << endl;Checkunsigned int i;vector recordingList;Recording currRecording;bool result;V* Your code goes here */for (i = 0; i < recordingList.size(); ++i) {currRecording = recordingList.at(i);currRecording. Print();}return 0;1CS Scanned with CutscenterNext level234 Use currRecording's ReadDiscount And Topic() to read each pair of inputs, character discount and string topic, until 'Z' is read frominput and currRecording's Read DiscountAnd Topic)) returns false. If currRecording's Read DiscountAnd Topic() returns true, appendcurrRecording to vector recording List.Ex: If the input is Y Housing Y Environment Y Jewelry Z, then the output is:Recording discount: Y, Topic: HousingRecording discount: Y, Topic: EnvironmentRecording discount: Y, Topic: Jewelry2930 }3132 int main() {33343536373839404243444546}cout << "Recording discount: "<< discount << ", Topic: " << topic << endl;Checkunsigned int i;vector recordingList;Recording currRecording;bool result;V* Your code goes here */for (i = 0; i < recordingList.size(); ++i) {currRecording = recordingList.at(i);currRecording. Print();}return 0;1CS Scanned with CutscenterNext level234

Initialize an empty vector called recordingList to store the recordings. Create a Recording object…

Answered: What would be missing line of code

Engineering

Computer Science

What would be missing line of code

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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In c++ Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, th backwards. End each loop with a newline. Ex: If courseGrades (7, 9, 11, 10), print: - 7 9 11 10 10 11 9 7 Hint Use two for loops. Second loop starts with i=NUM VALS-1. (Notes) Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element array (int courseGrades[4]) See How to Use zyBooks" Also note: If the submitted code tries to access an invalid array element, such as courseGrades[9] for a 4-element array, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message 2 using namespace std; 3 4 int main() { 5 6 7 8 9 10 11 12 13 14 const int NUM VALS-4; int courseGrades [NUM VALS]; int i; for (i-8; 1 NUM VALS; ++) { cin>> courseGrades[1]; } Your solution goes…
Use vectorized code free of for, while, and if commands
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