When a 0.740-g sample of trinitrotoluene (TNT), C,H,NO, is burned in a bomb calorimeter, the temperature increases from 23-4 °C to 26.9 °C. The heat capacity of the calorimeter is 534 J/°C, and it contains 675 mL of water. How much heat was produced by the combustion of the TNT sample? Give answer in kJ.

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Chapter5: Thermochemistry
Section: Chapter Questions
Problem 31E: When a 0.740-g sample of trinitrotoluene (TNT), C7H5N2O6, is burned in a bomb calorimeter, the...
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When a 0.740-g sample of trinitrotoluene (TNT), C,H,NO, is burned in a bomb calorimeter, the temperature increases
from 23-4 °C to 26.9 °C. The heat capacity of the calorimeter is 534 J/°C, and it contains 675 mL of water. How much
heat was produced by the combustion of the TNT sample? Give answer in kJ.
kJ
The addition of 3.15 g of Ba(OH), 8H,O to a solution of 1.52 g of NH SCN in 100 g of water in a calorimeter caused the
temperature to fall by 3.1 °C. Assuming the specific heat of the solution and products is 4.20 J/g °C, calculate the
approximate amount of heat absorbed by the reaction, which can be represented by the following equation:
Ba(OH), 8H₂O(s) + 2NH SCN(aq)-Ba(SCN),(aq) + 2NH, (aq) + 10H,O(1)
kJ
Transcribed Image Text:When a 0.740-g sample of trinitrotoluene (TNT), C,H,NO, is burned in a bomb calorimeter, the temperature increases from 23-4 °C to 26.9 °C. The heat capacity of the calorimeter is 534 J/°C, and it contains 675 mL of water. How much heat was produced by the combustion of the TNT sample? Give answer in kJ. kJ The addition of 3.15 g of Ba(OH), 8H,O to a solution of 1.52 g of NH SCN in 100 g of water in a calorimeter caused the temperature to fall by 3.1 °C. Assuming the specific heat of the solution and products is 4.20 J/g °C, calculate the approximate amount of heat absorbed by the reaction, which can be represented by the following equation: Ba(OH), 8H₂O(s) + 2NH SCN(aq)-Ba(SCN),(aq) + 2NH, (aq) + 10H,O(1) kJ
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