When labeling the loci on the map, the two outside loci must be in alphabetical order. For example, if you have the following loci: Albinism, Bone length, Cranial size, and Albinism is in the center, you would label the map Bone length - Albinism - Cranial size. Height 15.04 CM Color ◆ ; 1= 0.382 22.30 CM Mood Calculate the coefficient of coincidence and interference. Place your final answers in the spaces provided. Use three decimal places in your answer. Final answers: C = 0.618
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- Search the menus (Alt+/) A, ? 75% Normal text Calibri BI U A 11 + 1 | 2 6 9. Ishta, a female Yuan-ti, met Hisssteth, a male Yuan-ti, during sword training. He admired how quickly she moved using her powerful legs. She, in turn, was drawn to his skill as a sword fighter, using his tail ( for which she is homozygous) to slither about quietly with his weapon. Create a Punnett Square to show the possibilities that could result if Ishta and Hisssteth were to mate together and lay a clutch of eggs. Alleles (letters) and All Genotype and Phenotype Parent Punnett Square Phenotypes Possibilities Genotypes Genotype Phenotype Phenotype 9 of 17 Mom a. What is the probability of having a tailed baby? What is the probability of having a baby with legs?In investigating whether stress is a factor in aging, telomere length was measured in women with chronically ill children, and compared to the number of years since the child's diagnosis. Use the following summary data to calculate the correlation coefficient between telomere length and chronocity: Summary data: Sum of products: -11.564 Sum of squares for chronicity: 311.422 Sum of squares for telomere length: 2.499 Total sample size: 39The relationship between weight (in kilograms) and gender was estimated as below in a linear format. (Male was coded as 0 and Female was coded as 1.) Weight = -10.23 * Female + 66.73 (The p-value for the coefficient of Female is 0.03.) Base on the above equation, which of the following statements are true? (Select all that apply. There can be more than one answer.) Answer options: In the sample used to estimate the equation, the average weight of females is 66.23 kilograms In the sample used to estimate the equation, the average weight of females is 56.5 kilograms In the sample used to estimate the equation, the average weight of males is 66.73 kilograms Females are expected to weigh 10.23 kilograms less than males
- The geno. pe/s of people with freckles is/are: The genotype/s of people without freckles is/are:_ O Freckles: FF; No freckles: Ff, ff O Freckles: FF. Ff; No freckles: ff O Freckles: FF ff: No freckles: Ff O Freckles, f No freckles: FF, Ff4 E DFill up the Venn diagram with entries for each term. Where the circle intersects, place the SIMILARITIES of the terms. The rest of the spaces are for their specific differences.
- Example 3.5.7 Fish Vertebrae Consider the distribution of vertebrae given in Table 3.5.1. In Exam- ple 3.5.5 we found that the mean of Y is µy = 21.49. The variance of Y is VAR(Y) = of = (20 – 21.49) x Pr{Y = 20} 21) %3D + (21 – 21.49)? x Pr{Y + (22 – 21.49)? x Pr{Y = 22} + (23 – 21.49) x Pr{Y = 23} = (-1.49) x 0.03 + (-.49) x 0.51 + (0.51) x 0.40 + (1.51)² × 0.06 = 2.2201 x 0.03 + .2401 x 0.51 + .2601 x 0.40 + 2.2801 x 0.06 = 0.066603 + 0.122451 + 0.10404 + 0.136806 = 0.4299. The standard deviation of Y is ay = V0.4299 - 0.6557. %3DUse the scoring system described to calculate the alignment score for IPNI AAIG DV VAGP VKGIYA VG DV C-GK Scoring system: • Each identity results in +10 points. • Each gap has a penalty of -25 points. score = What is the percent identity (also called percent identity match)? percent identity: %The gels diagrammed below show the results of amplifying two VNTR loci from: 2 hairs found at a crime scene (hair 1 and hair 2), a crime victim, and possible suspects. Determine whom hair 1 could have belonged to based on the results in the gel below. If the hair could belong to more than one individual, then choose all of the possibilities. If the hair could not belong to any of these, choose "none of these". VNTR Locus 1 Hair 1 Hair 2 Victim Suspect 1 Suspect 2 Suspect 3 Suspect4 VNTR Locus 2 Hair 1 Hair 2 Suspect 1 Suspect 2 Suspect 3 Suspect 4 Victim Select one or more: O Victim O Suspect 1 O Suspect 2 O Suspect 3 O Suspect 4 O None of these
- Search the menus (Alt+/) I U A 90% Normal text Calibri 11 + B 2 | 3 |: 4 | 5 6 | 7 8 12. Male chickens (called roosters) have a red flap of skin growing from their heads called combs. These are used to attract female chickens (called hens). The bigger combs are called single combs. Roosters with single combs are more attractive to hens than those with smaller combs called rose combs. Saleh mates his hybrid single comb rooster named Sancho, to his favorite rose combed hen, named Maria so they can make baby chickens (chicks). Create a Punnett Square to show the possibilities that could result from this mating. Alleles and Phenotype All Genotype and Parent Genotypes Punnett Square Phenotype Possibilities Allele Phenotype Genotype Phenotype Dad Mom a. Maria's Genotype b. Sancho's Genotype 5 of 7 c. What is the probability of having a single comb chick? d. What is the probability of rose comb chick? e. What is the probability for a heterozygous?Cystic fibrosis (CF) recessive disorder in the Dutch population affects 1 in 1000 people. Calculate the heterozygote advantage for the cystic fibrosis gene (CFTR) in this population. Help: Square root of 0.001 is approximately equal to 0.03.Instruction: Fill up the table by computing the dominant alleles, recessive alleles and the Hardy-Weinberg equilibrium result of each generation. Lastly, make a short conclusion below. Show the complete solution. Hardy-Weinberg Equilibrium Generation Dominant allele Recessive allele 1 35 65 2 50 50 3 73 27 Conclusion: