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- Match the reaction with the mechanism that it proceeds through. HO, HO. X catalytic H₂SO4 HBr Br₂ light 1. Free Radical Chain Reaction 2. SN1 3. SN2 4. E1 5. E2As we will learn, many antioxidants–compounds that prevent unwanted radical oxidation reactions from occurring–are phenols, compounds that contain an OH group bonded directly to a benzene ring.a.) Explain why homolysis of the O–H bond in phenol requiresconsiderably less energy than homolysis of the O–H bond in ethanol(362 kJ/mol vs. 438 kJ/mol).b.) Why is the C–O bond in phenol shorter than the C–O bond in ethanol?What is the mechanism of this reaction? Plz do Asap...!
- ! ( plz give reaction and its mechanism)CH,CH,СH, CI CH,СНHCICH, + 2HCI 2CH,CH,СH, + 2C1, The chlorination of propane proceeds as a radical chain reaction. Sort the 7 reaction steps (you may need to scroll down to see them all) into categories of: Initiation Propagation Termination сн, сH,CH,. CH3CH2CH2 CH,CH, CH, -di: сHсHCH- di: а — б: — 2б Cl CH3CH2CH2 CнснсH. СH,сH,CH, -н CH3CHCH3 н— н—й: сн,бнсн, CH,CнсH, CH CHCH сH,снсH,6) Write the mechanism (two propagation steps only, starting with the bromine radical in the first step and using Br2 in the second step) and that would explain how the following two products are produced. (Hint – the allylic radical is resonance stabilized.) Br Br NBS
- In the E2 reaction of 2-bromopentane with sodium tert-butoxide, 1-pentene is favored over 2- pentene. It is based on O the size of base used. O the Zaisev's rule. O the strength of the base used. O the Hoffman product. O the stability of alkeneOn Show the mechanism of that ои Br 2 Моде њ Br Lon -Br reactionWhich mechanism(s) would be favored under the following reaction conditions?
- In an Sn2 reaction with "CN as nucleophile, [CH:CH:CI | CH:CH;OH_ CH;CH;0Tos] reacts faster because it has a [better / poor] leaving group than the other ones. These types of leaving groups can stabilize the developing [positive charge / negative charge / radical] in the transition state thus lowering Jenthalpy / entropy / aetivation energy]. CH;CH2CH2B1 reacts faster in [water/ CH:CN]. In a polar [protic / aprotic] solvent, the negatively charged nucleophile will be solvated thus becoming more stable and [more / less]reactive.Determine the mechanism of nucleophilic substitution of each reaction and draw the products, including stereochemistr CH₂CH3 CI Br + CN d. + CH3COOH a. acetone + -OCH3 e. DMF f. b. C. ||||| a ||||| Br H Br CH2CH2CH3 + CH3OH DMSO H CH3 CI Br + OCH₂CH3 + CH3CH₂OH2. Propose electron-pushing arrows for each step of the radical mechanism shown below. PhO,s.-so,Ph jor for > H [w-o [w-o Pho2s-sO,Ph H