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- Deduce the identity of the following compound from the spectral data given. C8H10: 1H NMR, 6 1.20 (3H, triplet), 2.60 (2H, quartet), 7.12 (5H, singlet) (ppm); IR, 3050, 2970, 1600 cm-1; MS, m/z 91A compound with the molecular formula C13H1803 gave the following IR, 13C NMR, and ¹H NMR spectra: C₁H00 LOD 4100 200 CDS-02-401 180 160 140 doublet 2H 9 HSP-43-267 triplet 2H triplet 1H 8 6 2003 120 100 There are eleven peaks on the spectrum. 5 ppm HAVENUMBER- 4 ppm The the structure of the compound is: triplet 2H triplet 2H 80 60 triplet 2H 1500 40 20 triplet 3H quintet 2H sextet 2H 1 0 0 1000Which of the following reactions will synthesize phenol from benzene? 1) HNO3 + H2SO4; 2) Fe, HCl; 3) NaNO2, HCl, 0-10 oC; 4) warm H2SO4 and H2O 1) HNO3 + H2SO4; 2) Fe, HCl; 3) NaNO2, HCl, 0-10 oC; 4) CuCN; 5) dilute acid and heat 1) Acetyl chloride & AlCl3; 2) bleach 1) Ph-N2+ + KI; 2) BrMgCH=CH2 in ether, followed by H3O+; 3) warm, conc'd KMnO4 1) Cl-CH(CH3)-CH2CH2CH3 + FeBr3; 2) hot, conc'd KMnO4
- 1. Propose a structure consistent with following spectral data for a compound C8H18O2: IR: 3350 cm-1 'H NMR: 1.24 8 (12 H, singlet); 1.56 8 (4 H, singlet); 1.95 ô (2 H, singlet)13:22 4G O 5 ê © T Ô 1. What is the correct IUPAC name for the following compound? Q A. Diphenylamine 1,1 diphenylamine OCN,N-diphenylamine O D. None of the above is correct Add a caption... > Status (Custom) +An aromatic hydrocarbon with a molecular formula of C13H20 has an 1H NMR spectrum with a signal at ~7 ppm that integrates to 5H. It also has twosinglets; one of the singlets has 1.5 times the area of the second. What is the structure of the aromatic hydrocarbon?
- An aromatic hydrocarbon with a molecular formula of C13H20 has an 1H NMR spectrum with a signal at ~7 ppm that integrates to 5H. It also has two singlets; one of the singlets has 1.5 times the area of the second. What is the structure of the aromatic hydrocarbon?An unknown compound has a molecular formula of C,H,O. Its IR spectrum shows prominent absorptions at 2980, 2960, and 1718 cm . It exhibits the following signals in its H NMR spectrum (ppm): 1.06 (triplet, 3H), 2.12 (singlet, 3H), 2.45 (quartet, 2H); and the following signals in its ¹3C NMR spectrum ( ppm): 7.6, 29.5, 36.8, 208.8. Draw the structure of the unknown compound. Click and drag to start drawing a structure. 0 X 0:0An aromatic hydrocarbon with a molecular formula of C13H20 has an 1 H NMR spectrum with a signal at ~7 ppm that integrates to 5H. It also has two singlets; one of the singlets has 1.5 times the area of the second. What is the structure of the aromatic hydrocarbon?
- 9a) The proton bonded to the carbon adjacent to the carbonyl group in the following compound can be classified into which chemical shift in the ¹H-NMR spectra of aldehydes and ketones? R or H H - 10.0-12.0 ppm R H -2.0-3.0 ppm NO₂ N (1) 9b) Choose the one below that could be resolved into enantiomers. (1) alpha hydrogens = ? ppm NO₂ NO₂ 9c) Which of the following is the major product of the reaction below. `N H -5.0-7.0 ppm (11) (11) -0.0-1.0 ppm HNO3, H₂SO4 H NO₂ (III) NO₂ (1) and (II) (IV) None of the options (IV)Please Annotate the 1H NMR and 13C NMR. The structure is Cyclopentanone C5H8O :)Identify below compound from its spectral data. Molecular formula:C3H5ClO2 IR:3500–2500 cm−1, 1714 cm−1 1H NMR data:2.87 (triplet, 2 H), 3.76 (triplet, 2 H), and 11.8 (singlet, 1H) ppm