With function: void swapNum(int n1, int n2) { int temp = n%; %3D n1 = n2; n2 = temp; %3D And with a=4, b=5, after executing swapNum(a, b), we should have a=5 and b=4. a. False b. True
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- int p =5 , q =6; void foo ( int b , int c ) { b = 2 * c ; p = p + c ; c = 1 + p ; q = q * 2; print ( b + c ); } main () { foo (p , q ); print p , q ; } Explain and print the output of the above code when the parameters to the foo function are passed by value. Explain and print the output of the above code when the parameters to the foo function are passed by reference. Explain and print the output of the above code when the parameters to the foo function are passed by value result. Explain and print the output of the above code when the parameters to the foo function are passed by name.Write these in Pseudocode #1a – In pseudocode, write a call to a function that passes 1 Integer variable and 1 Integer array, and saves a Boolean value in return. #1b – In pseudocode, write the function that accepts 1 Integer and 1 Integer array and returns a Boolean. In the function, search the Integer array with a for-loop, and if the Integer parameter is found in the array, return false. If the Integer parameter is not found, return true. #2a – In pseudocode, write a call to a module that passes 1 Integer variable, 1 Real variable, 1 String constant, and 1 String literal as arguments. #2b – In pseudocode, write the module header that accepts 1 Integer, 1 Real, and 2 Strings as parameters. #3 – This pseudocode has multiple problems. Fix the calling statement and the definition below so that the routine accepts 3 grades as parameters and returns the average into a variable.…Consider the following function: public void bSearch(int[] A, int value, int start, int end) { if (end value) { return bSearch(A, value, start, mid); } else if (value > A[mid]) { return bSearch(A, value, mid+1, end); } else { return mid; } } The mutation program P' changes the part as shown below. } else if (value > A[mid]) { return bSearch(A, value, mid+2, end); } else { return mid; } A test input is given t1: {A = [2, 3, 5, 7, 10, 11], value = 6, start=0, end=5}. Which statement below best describes the mutant with regards to the test input? O a. t1 resolves mutant P O b. The mutant P' with regards to test input t1 is live.
- Assume that: int x[5] = {2,4,5,7,8}; What are the values of x after calling: swap(x+2, x+4); swap(x+1, x+3); if the swap function is defined as follows void swap(int *a, int *b) { int t; t=*b; *b=*a; *a=t;} Select one: O a. {2,7,5,4,8} O b. {2,4,5,7,5} O c. {2,4,5,4,5} O d. {2,7,8,4,5}A pentagonal number is defined as for and so on. So, the first few numbers are 1, 5, 12, 22, .... Write a function with the following header that returns a pentagonal number:def getPentagonalNumber(n):Write a test program that uses this function to display the first 100 pentagonal numbers with 10 numbers on each line.Part (a) Write a python function that computes the binomial coefficient ("). The function should return the correct answer for any positive integer n and k where k=m pass Part (c) Suppose that the number of people in the trial is 100. Then: • Plot a curve that shows how the probability of type 1 error changes with the choice of m, for m = 1,...n assuming that the null hypothesis holds (in red), • On the same picture, plot the probability of type 2 error vs the value of m in the case in which the new drug is effective with proability 0.68 (in blue). You can plot the two curves using matplotlib.pyplot. You can select the color by passing color='r' or color='b' to the plt.plot() function. [4]: n - 100 # your code here def plot_curve (): pass [5]: plot_curve() Part (d) Based on the picture above, what value of m do you think would be suitable to keep both type 1 and type 2 error small at the same time? (You may assume that the company claims the new drug has 68% accuracy) [6]: # your…
- 1. void Foo(int A[]) { 2. let c = A.size(); 3. for (i = 1 to c^2) { 4. Boo(i); 5. 6. j = c; 7. while (j> 1) { 8. } //end for print "hello"; 9. j=j/y; 10. }//end while 11.} If we are given that is a function whose asymptotic runtime is cubic in the input i.e. . What is the asymptotic run time of Воо Boo(n) = O(n³) FooWrite a program that generates random numbers between -25 and 25 by using the randint function. The program will add up the numbers and terminate when the sum of the values becomes zero. The program should contain the following functions: add() : add up the values main(): the function where the program execution should begin and end. randomgen(): a function that returns a number between -25 and 25 A global variable subsetsum that keeps track of the sum The program should output the count of the number of values generated before exiting saying that the subset sum was zero.Let A = {a, b, c} and B = {u, v}. Write a. A × B b. B × A
- Create a program that accepts an integer N, and pass it to the function generatePattern. generatePattern() function which has the following description: Return type - void Parameter - integer n This function prints a right triangular pattern of letter 'T' based on the value of n. The top of the triangle starts with 1 and increments by one down on the next line until the integer n. For each row of in printing the right triangle, print "T" for n times. In the main function, call the generatePattern() function. Input 1. One line containing an integer Output Enter N: 4 T TT TTT TTTTPb#1: For several values of x, confirm that eix = cos x + i sin x Pb#2: An object thrown vertically with a speed vo reaches a height h at time t, where h= vo*t - gt2 Write and test a function that computes the time t required to reach a specified height h, for a given value of vo. The function's inputs should be h, vo, and g. Test your function for the case where h=100 m, vo=50 m/s. and g=9.81 m/s2. Interpret both answers. (MATLAB)2. code locations Consider the following C code and the corresponding assembly code: void baz(int a, int * p) { pushq %rbp movq %rsp,%rbp subq $16,%rsp int c; C = a-*p; movl %ecx,16(%rbp) movq %rdx, 24(%rbp) movq 24(%rbp), %rax movl (%rax),%eax movl 16(%rbp),%edx subl %eax,%edx movl %edx,%eax movl %eax,-4(%rbp) cmpl $0, -4(%rbp) je L2 if (c) { int d = c*2; movl -4(%rbp),%eax addl %eax,%eax movl %eax,-8(%rbp) *p -= d; movl 24(%rbp),%rax movl (%rax),%eax subl -8(%rbp),%eax movl %eax,%edx movq 24(%rbp), %rax movl %edx, (%rax) jmp L4: (continued on next page)
